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我有一个动态选项列表字段,其中包含组织中所有顶点类名称。页面上还有一个“显示”按钮。现在如果用户从这个选项列表中选择一个值并点击显示按钮,那么该类的顶点代码应该显示在下面。 请建议我如何在我的VF页面中实现它。单击“显示”按钮时显示顶点类代码
谢谢!点击该按钮时
public class SomeController {
private List<ApexClass> allApexClasses;
public String selectedClass {public get; public set;}
public String apexCodeOutput {public get; private set;}
public SomeController() {
// only select classes that aren't part of a managed package, since you won't be able to view the body
allApexClasses = [select id, name, body from ApexClass where lengthwithoutcomments <> -1 order by name asc];
}
public List<SelectOption> getClassList() {
List<SelectOption> opts = new List<SelectOption> opts;
for (ApexClass ac : allApexClasses)
opts.add(new SelectOption(ac.Id, ac.Name));
return opts;
}
public PageReference show() {
if (selectedClass != null) {
Id classId = (Id) selectedClass;
for (ApexClass ac : allApexClasses) {
if (classId == ac.Id) {
apexCodeOutput = ac.body;
break;
}
}
}
return null;
}
}
,然后在VF页,只需重新呈现输出代码:
<apex:form >
<apex:selectList value="{!selectedClass}" size="5">
<apex:selectOptions value="{!ClassList}" ></apex:selectOptions>
</apex:selectList>
<apex:pageBlock >
<apex:commandButton action="{!show}" value="Show" id="Button"/>
<apex:pageBlockSection title="My Current Class">