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将Django 1.9与Python 3.5,我想作一个简单的搜索页面:Django的 - 简单的搜索
views.py
from django.views import generic
from django.shortcuts import render
from .models import Movie, Genre
class IndexView(generic.ListView):
template_name = 'movies/index.html'
page_template = 'movies/all_movies.html'
context_object_name = 'all_movies'
model = Movie
def get_context_data(self, **kwargs):
context = super(IndexView, self).get_context_data(**kwargs)
context.update({
'all_genres': Genre.objects.all(),
'page_title': 'Latest'
})
return context
def get_queryset(self):
query = request.GET.get('q')
if query:
return Movie.objects.filter(title__icontains=query)
else:
return Movie.objects.all()
形式
<form method="GET" action="" id="searchform">
<input class="searchfield" id="searchbox" name="q" type="text" value="{{ request.GET.q }}" placeholder="Search..."/>
</form>
由于某种原因我不断收到错误:
name 'request' is not defined
我不太确定我做错了什么,任何帮助将不胜感激。
是的!那完美的作品。谢谢! – mari