如何在.Net中实现动态部分XML类序列化？

Question

我很想使用默认的.Net xml序列化器将我的数据保存为简单的xml格式。我有一个enum MemberCode { feild1 = 1, feild2 = 2 /*...*/}在运行时，我生成List<MemberCode>我想保存到XML（有时更少有时）的成员。

如何实现这样的部分类序列化？

Answer 1

以下代码可能会解决您的问题。

我们创建了一个名为MemberList的可序列化的类，它包含一个MemberCodes数组。在运行时填充成员代码列表后，我们将其转换为数组并将其序列化为XML。结果将被保存到调试文件夹中名为“test.xml”的文件中。

XML输出

<?xml version="1.0" encoding="utf-8"?> 
    <MemberList xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"> 
     <Members> 
     <Member>Field1</Member> 
     <Member>Field2</Member> 
     <Member>Field3</Member> 
     <Member>Field2</Member> 
     <Member>Field1</Member> 
     <Member>field4</Member> 
     </Members> 
    </MemberList> 

代码：

using System; 
using System.Collections.Generic; 
using System.IO; 
using System.Xml.Serialization; 

namespace ConsoleApplication1 
{ 
    public class Program 
    { 
     static void Main(string[] args) 
     { 
      // Your member code list 
      List<MemberCode> list = new List<MemberCode>(); 

      // Add some members to the list during runtime (replace with your logic) 
      list.Add(MemberCode.Field1); 
      list.Add(MemberCode.Field2); 
      list.Add(MemberCode.Field3); 
      list.Add(MemberCode.Field2); 
      list.Add(MemberCode.Field1); 
      list.Add(MemberCode.field4); 

      // Create a new serializable member list 
      MemberList memberList = new MemberList(); 
      // Convert your list to a serializable array 
      memberList.MemberCode = list.ToArray(); 

      // Write the XML to a file 
      XmlSerializer serializer = new XmlSerializer(typeof(MemberList)); 
      TextWriter writer = new StreamWriter("test.xml"); 
      serializer.Serialize(writer, memberList); 

      Console.ReadLine(); 
     } 
    } 

    [XmlRoot] 
    public class MemberList 
    { 
     [XmlArray("Members")] 
     [XmlArrayItem("Member", typeof(MemberCode))] 
     public MemberCode[] MemberCode { get; set; } 
    } 

    public enum MemberCode 
    { 
     Field1 = 1, 
     Field2 = 2, 
     Field3 = 3, 
     field4 = 4 
    } 
}