2012-02-02 30 views
0

我可以noob我想要的是将一个NSDictionary对象转换为NSInteger.im解析json对象并将其存储在一个NSMutableArray中,然后存储在NSDictionary对象中,称为boy.could you guys帮助我out.below是代码。如何将一个NSDictionary值转换为NSInteger

 NSURLRequest *request = [NSURLRequest requestWithURL:jsonurl cachePolicy:NSURLRequestUseProtocolCachePolicy timeoutInterval:60.0]; 
connection1=[[[NSURLConnection alloc] initWithRequest:request delegate:self] autorelease]; 


NSLog(@"jsonurl:%@",jsonurl); 
self.jsonData=[NSData dataWithContentsOfURL:jsonurl]; 

NSDictionary *items=[NSJSONSerialization JSONObjectWithData:self.jsonData options:NSJSONReadingMutableLeaves error:nil]; 
NSLog(@"blah:%@",jsonArray); 
items1 = [items objectForKey:@"ThingsTodo"]; 

story = [[NSMutableArray array]retain]; 
media1 = [[NSMutableArray array]retain]; 

url=[[NSMutableArray array]retain]; 
media2=[[NSMutableArray array]retain]; 
descriptiondesc=[[NSMutableArray array]retain]; 
for (NSDictionary *item in items1) 
{ 
    [self.story addObject:[item objectForKey:@"Name"]]; 
    [self.media1 addObject:[item objectForKey:@"Status"]]; 
    [self.media2 addObject:[item objectForKey:@"Image"]]; 

} 
    NSDictionary *boy=[self.media1 objectAtIndex:indexPath.row]; 

回答

5

把你nsdictionary价值为nsstring然后采取NSInteger和不喜欢:

NSInteger n = [strVal intValue]; 
+0

k会试一试... – stephensam 2012-02-02 05:19:42

+0

感谢它的工作 – stephensam 2012-02-02 05:29:40

0

更具体 “的intValue” 给出了 “INT”,而 “integerValue” 返回 “NSInteger的”,所以

NSInteger n = [strVal integerValue];