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确保自引用PHP表单的逻辑测试正确识别用于提交表单的HTML按钮时,如果实际通过jquery.submit提交表单,什么才是最好的方法() - 而不是点击按钮本身?
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<title> Total Tutor </title>
<link type="text/css" rel="stylesheet" href="course.css">
<script src="../jquery.js"></script>
</head>
<body>
<script>
$(document).ready(function() {
//event that triggers the javascript/jquery form submission
$('li').dblclick(function()
{
selectedCourse=$(this).text();
sessionStorage.removeItem('selectedCourse');
sessionStorage.setItem('selectedCourse', selectedCourse);
editForm();
});
//the function called by the normal button submission and the alternative jQuery only submission: note the non jQuery one sets the $-POST variable fine
function editForm() {
var s= confirm('Would you like to edit ' +selectedCourse+ '');
if(s)
{
alert('form is called');
}
}
$('#edit-button').click(function() { editForm(); });
});
</script>
<?php
if(!isset($_POST['submit']))
{
?>
<ul>
<li>Maths</li>
<li>English</li>
</ul>
<form id="edit_delete" method="POST" action=" <?php echo $_SERVER['PHP_SELF']; ?>">
<button type="submit" id="edit-button" name="submit" value="edit" ><img src="../images/pencil.png"></button>
<button type="submit" id="delete-button" name="submit" value="delete" ><img src="../images/deleteo.png"></button>
</form>
}
<?php
else
{
if($_POST['submit']=='edit')
{
?>
<p>Thank you for selecting edit</p>
<?php
}
if($_POST['submit']=='delete')
{
?>
<p>Thank you for selecting delete</p>
<?php
}
}
?>
</body>
</html>
不会这只是告诉我表单已经提交 - 它不会告诉我编辑或删除按钮是否被触发? – jon
如果'$ _POST ['wasClicked'] ==“0”'的值,那么它是由编辑按钮触发的。这里的关键原则是将隐藏的输入字段设置为您提交的值_before_,以查看哪个方法触发了提交 –