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我没有真正了解扫描器的行为。我想先输入一个int,然后在while循环中输入下一行输入。但是在第一次输入后,我得到一个ArrayOutOfBoundsException,如下所示。它只是忽略了我想输入下一行。唯一的解决方案是当我输入int和新行在一行中用空格分隔时,但这不是我想要的,因为此时用户不知道在第一个int后输入什么。Java扫描器不期望下一个输入,忽略nextLine()
Scanner scanner = new Scanner(System.in);
int i = scanner.nextInt() - 1;
logic.setGameField(games.get(i).getGameField());
// scanner.reset(); //what does that do?
view.displayField(logic.getCompleteGameField(), logic.getGameSize(), logic.getCompleteGameSize());
double time = System.currentTimeMillis();
while (!logic.gameIsFinished()) {
System.out.println("Spalte Reihe Zeichen: X/*");
String s = scanner.nextLine();
char[] tmp = s.toCharArray();
//just for testing
System.out.println(s.length()); //outputs: 0
System.out.println(tmp.length); //outputs: 0
for (int j = 0; j < tmp.length; j++) {
System.out.print(tmp[j] + " " + j);
}
System.out.println();
logic.setSingleField(tmp[1] - CHAR_TO_INT_OFFSET_ROW, tmp[0] - CHAR_TO_INT_OFFSET_COLUMN, tmp[2]); //throws as expected ArrayIndexOutOfBoundsException
'System.out.println(s.length()); // outputs:0'所以当你使用'tmp [2]','tmp [1]'或'tmp [0]'时,你期望什么? – 2017-04-23 16:01:06