合并两个哈希

Question

我有2个哈希有键和值

h1 = {"January"=>1, "February"=>2, "March"=>4, "April"=>5, "May"=>5, "June"=>6} 

h2 = {1=>3, 2=>5, 3=>10, 4=>12, 6=>14} 

而且我希望有一个像

result = {3=>1, 5=>2, 10=>4, 12=>5, 14=>6} 

如果你想1我试过这个解决方案

结果返回两个“第一”和“一”，你需要将它们存储在 一个数组那么这将是这1所映射到的值。

results = {} 

    hash1.each do |key, value| if results[key].nil? 
    results[key] = [value] else 
    results[key] << value 

hash2.each do |key, value| if results[key].nil? 
    results[key] = [value] else 
    results[key] << value 

results[1] 
# => ["one", "first"] 

但我的结果是

{1=>[3], 2=>[5], 3=>[10], 4=>[12], 6=>[14], "January"=>[1], "February"=>[2], "March"=>[4], "April"=>[5], "May"=>[5], "June"=>[6]} 

Answer 1

这是因为你在一个列表sorround它，尽量做的跟随着，并不需要做第二foreach循环：

Recomended way：

hash1 = {"January"=>1, "February"=>2, "March"=>4, "April"=>5, "May"=>5, "June"=>6} 

hash2 = {1=>3, 2=>5, 3=>10, 4=>12, 6=>14} 

results = {} 

#here you have to swap key-value for value-key 

hash2.each do |value, key| 
    if results[key].nil? 
    results[key] = value 
    else 
    results[key] << value 
    end 
end 

results 

=> {3 => 1，5 => 2，10 => 3，12 => 4，14 => 6}

替代方式：

可以压缩的两个列表，键中的一个，另一个的值，然后把它们在字典中：

hash1 = {"January"=>1, "February"=>2, "March"=>4, "April"=>5, "May"=>5, "June"=>6} 

hash2 = {1=>3, 2=>5, 3=>10, 4=>12, 6=>14} 

results = {} 

(hash2.values).zip(hash1.values).each do |key, value| 
    if results[key].nil? 
    results[key] = value 
    else 
    results[key] << value 
    end 
end 

results 

=> {3 => 1，5 => 2，10 => 4，12 => 5 ，14 => 5}