我对PHP编程还很陌生,我环顾四周,但我仍然感到困惑。我试图更新我的用户表中的图像路径,我不太确定如何去做。这是我将图像放入数据库的代码,它可以插入图像,但我不确定如何更新数据库中的图像图片路径以使用新插入的图像,而不是使用者当他们创建一个帐户时选择。更新图像路径
// Make sure we didn't have an error uploading the image
($_FILES[$image_fieldname]['error'] == 0)
or handle_error("the server couldn't upload the image you selected.",
$php_errors[$_FILES[$image_fieldname]['error']]);
// Is this file the result of a valid upload?
@is_uploaded_file($_FILES[$image_fieldname]['tmp_name'])
or handle_error("you were trying to do something naughty. Shame on you!",
"upload request: file named " .
"'{$_FILES[$image_fieldname]['tmp_name']}'");
// Is this actually an image?
@getimagesize($_FILES[$image_fieldname]['tmp_name'])
or handle_error("you selected a file for your picture " .
"that isn't an image.",
"{$_FILES[$image_fieldname]['tmp_name']} " .
"isn't a valid image file.");
// Name the file uniquely
$now = time();
while (file_exists($upload_filename = $upload_dir . $now .
'-' .
$_FILES[$image_fieldname]['name'])) {
$now++;
}
// Finally, move the file to its permanent location
@move_uploaded_file($_FILES[$image_fieldname]['tmp_name'], $upload_filename)
or handle_error("we had a problem saving your image to " .
"its permanent location.",
"permissions or related error moving " .
"file to {$upload_filename}");
$insert_sql = "UPDATE users set user_pic_path WHERE user_id = $user_id =
replace(user_pic_path, '$upload_filename', '$upload_filename');
//insert the user into the database
mysql_query($insert_sql);
</code>
编辑: 我失踪了“这是我固定的,现在还没有SQL错误,它把图片放到数据库,但不能取代在数据库中的图像路径我已经搞乱?在$ INSERT_SQL,但它仍然没有更新为新图像路径数据库,我能做些什么这是我的新的更新代码:
<code>
$insert_sql = "UPDATE users WHERE user_id = $user_id set user_pic_path =
replace(user_pic_path, '$upload_filename', '$upload_filename')";
</code>
所以,你没有任何计划或编码技巧,对吧?我敢打赌,有一些文件,你从哪里得到这些代码。 – djot
你觉得'user_pic_path'代表什么? – djot
我确实有一些编程技巧,我只是比较新的PHP和坚持这一点。我不确定要在$ insert_sql中放入什么来更新数据库中的映像路径。它可以很好地将图像放入数据库,但它不会替换路径,这正是我期望做的 – nikito2003