top命令特殊字符

在以下命令我得到alert.txt的特殊字符前output.How我可以阻止它....top命令特殊字符

#!/bin/sh 
topsnapshot=`top -n 5` 
    echo -e "\n\n===========================TOP COMMAND SNAPSHOT====================================================" > /tmp/alert.txt 
echo "$topsnapshot" >> /tmp/alert.txt

输出：

===========================TOP COMMAND SNAPSHOT==================================================== 
    ^[[H^[[2J^[(B^[[mtop - 18:56:01 up 112 days, 18:22, 5 users, load average: 0.99, 0.73, 0.33^[(B^[[m^[[39;49m^[[K 
    Tasks:^[(B^[[m^[[39;49m^[(B^[[m 142 ^[(B^[[m^[[39;49mtotal,^[(B^[[m^[[39;49m^[(B^[[m 2 ^[(B^[[m^[[39;49mrunning,^[(B^[[m^[[39;49m^[(B^[[m 139 ^[(B^[[m^[[39;49msleeping,^[(B^[[m^[[39;49m^[(B^[[m 0 ^[(B^[[m^[[39;49mstopped,^[(B^[[m^[[39;49m^[(B^[[m 1 ^[(B^[[m^[[39;49mzombie^[(B^[[m^[[39;49m^[[K 
    Cpu(s):^[(B^[[m^[[39;49m^[(B^[[m 0.2%^[(B^[[m^[[39;49mus,^[(B^[[m^[[39;49m^[(B^[[m 0.2%^[(B^[[m^[[39;49msy,^[(B^[[m^[[39;49m^[(B^[[m 0.0%^[(B^[[m^[[39;49mni,^[(B^[[m^[[39;49m^[(B^[[m 99.1%^[(B^[[m^[[39;49mid,^[(B^[[m^[[39;49m^[(B^[[m 0.4%^[(B^[[m^[[39;49mwa,^[(B^[[m^[[39;49m^[(B^[[m 0.0%^[(B^[[m^[[39;49mhi,^[(B^[[m^[[39;49m^[(B^[[m 0.0%^[(B^[[m^[[39;49msi,^[(B^[[m^[[39;49m^[(B^[[m 0.0%^[(B^[[m^[[39;49mst^[(B^[[m^[[39;49m^[[K 
    Mem: ^[(B^[[m^[[39;49m^[(B^[[m 4142428k ^[(B^[[m^[[39;49mtotal,^[(B^[[m^[[39;49m^[(B^[[m 2291280k ^[(B^[[m^[[39;49mused,^[(B^[[m^[[39;49m^[(B^[[m 1851148k ^[(B^[[m^[[39;49mfree,^[(B^[[m^[[39;49m^[(B^[[m 569928k ^[(B^[[m^[[39;49mbuffers^[(B^[[m^[[39;49m^[[K 
    Swap:^[(B^[[m^[[39;49m^[(B^[[m 5668856k ^[(B^[[m^[[39;49mtotal,^[(B^[[m^[[39;49m^[(B^[[m  76k ^[(B^[[m^[[39;49mused,^[(B^[[m^[[39;49m^[(B^[[m 5668780k ^[(B^[[m^[[39;49mfree,^[(B^[[m^[[39;49m^[(B^[[m 1088948k ^[(B^[[m^[[39;49mcached^[(B^[[m^[[39;49m^[[K 
    ^[[6;1H 
    ^[[7m PID USER  PR NI VIRT RES SHR S %CPU %MEM TIME+ COMMAND                         ^[(B^[[m^[[39;49m^[[K 
    ^[(B^[[m^[(B^[[m31832 root  25 0 6072 2100 1228 R 99.2 0.1 6:40.14 t.py                          ^[(B^[[m^[[39;49m 
    ^[(B^[[m 1 root  15 0 2160 644 556 S 0.0 0.0 0:17.83 init

来源

2012-03-29 Rajeev

$顶部-n 1 -B |头> /tmp/alert.txt – lancha90 2014-01-21 11:28:45

尝试：

topsnapshot=`top -b -n 5`

来源

2012-03-29 14:29:59

-b输出靠前指挥5倍，我不希望出现这种情况 – Rajeev 2012-03-29 14:31:46

所以*你*你想要什么？你想在五秒钟后读一读吗？还是只读一读？没有-b，你实际上只能获得五次读数中的最后一次。 – 2012-03-29 14:51:13

然后更改选项。 – tripleee 2012-03-29 14:56:01

这对我的作品在Linux上：

topsnapshot=$(TERM=dumb top -n 5)

的哑终端没有转义序列。

来源

2012-03-29 14:40:51

虽然输出中没有格式化和只有一个输出顶部在output.Thsi结果5次命令重复-n 5 – Rajeev 2012-03-29 14:50:24

你怎么确定它是不是格式化？如果我这样做：'echo“$ topsnapshot”'，我得到整齐格式的数据。如果我这样做：'echo $ topsnapshot'，然后我得到一团糟。这是可以预料的;否则它的外壳会变得行为不端。 – 2012-03-29 14:52:07

另外，'-n 5'选项表示“产生5个批次的输出”。如果你只想要一个，那么使用'top -n 1'。 '-n 5'直接来自你的问题。当去直接筛选，花哨的格式化字符（终端控制字符）意味着你只能看到一个大量输出的时间，但'top'程序生成5个屏幕十足。 – 2012-03-29 17:10:15

您已在您的意见，你不希望它重复5次，但在你的例子命令使用-n 5其他的答案。 -n 5告诉top重复5次。因此，尝试以下操作来得到它只有一次重复：

topsnapshot=$(top -b -n 1)

如果你只是想输出的前几行，用head：

topsnapshot=$(top -b -n 1 | head -n 25)

要打印捕获的输出，我提出以下建议：

printf '%s\n' "${topsnapshot}"

一定要记住${topsnapshot}左右的双引号。我不使用echo，因为它取决于shell的实现，它是may or may not treat backslashes specially。

来源

2012-03-29 15:13:23

top命令特殊字符

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