XSLT 1.0中的序列号

Question

您需要一些帮助XSLT格式化用于创建序列号元素标记。主要是元素标签错过了一些数字的顺序，我需要得到一个顺序格式的输出，如下所示，通过添加缺失的数字元素标签在相同的序列座位标签。

任何帮助，在此非常感谢，提前感谢。

输入

<book> 
<Seat> 
    <seatNumber>12A</seatNumber> 
    <Element>1</Element> 
    <Number>1</Number> 
</Seat> 
<Seat> 
    <seatNumber>12B</seatNumber> 
    <Element>3</Element> 
    <Number>1</Number> 
</Seat> 
<Seat> 
    <seatNumber>12C</seatNumber> 
    <Element>4</Element> 
    <Number>1</Number> 
</Seat> 
<Seat> 
    <seatNumber>12D</seatNumber> 
    <Element>5</Element> 
    <Number>1</Number> 
</Seat> 
<Seat> 
    <seatNumber>12E</seatNumber> 
    <Element>7</Element> 
    <Number>1</Number> 
</Seat> 
</book> 

输出

<book> 
<Seat> 
    <seatNumber>12A</seatNumber> 
    <Element>1</Element> 
    <Number>1</Number> 
</Seat> 
<Seat> 
    <seatNumber>12B</seatNumber> 
    <Element>2</Element> 
    <Number>1</Number> 
</Seat> 
<Seat> 
    <seatNumber>12C</seatNumber> 
    <Element>3</Element> 
    <Number>1</Number> 
</Seat> 
<Seat> 
    <seatNumber>12D</seatNumber> 
    <Element>4</Element> 
    <Number>1</Number> 
</Seat> 
<Seat> 
    <seatNumber>12E</seatNumber> 
    <Element>5</Element> 
    <Number>1</Number> 
</Seat> 
</book> 

Answer 1

试试这样说：

XSLT 1.0

<xsl:stylesheet version="1.0" 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> 
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/> 
<xsl:strip-space elements="*"/> 

<!-- identity transform --> 
<xsl:template match="@*|node()"> 
    <xsl:copy> 
     <xsl:apply-templates select="@*|node()"/> 
    </xsl:copy> 
</xsl:template> 

<xsl:template match="Element"> 
    <xsl:copy> 
     <xsl:number count="Seat"/> 
    </xsl:copy> 
</xsl:template> 

</xsl:stylesheet>