如何填充不同值的数组

Question

我想要我的数组输入，使其不能有相同的数字两次： 但是这将有一个输出 “值存在，请重新输入：”; 两次。我如何检查它是否是唯一的，如果它之前已经初始化，只显示一次？

int main(){ 
    int arr_size = 10; 
    int value; 
    int aArray[10]; 
    for(int i=0;i<arr_size;i++) 
    { 
     cout<<"enter value of slot"<<i+1<<": "; 
     cin>>value; 

     for(int j=0;j<arr_size;j++){ 

      if(value == aArray[j]) 
      { 
      cout<<"value exist please re enter: "; 
      cin>>value; 
      } 
      else{ 

      aArray[i] = value; 
      } 
     } 
    } 

    } 

Answer 1

更改为：

for(int i=0;i<arr_size;i++) 
    { 
     cout<<"enter value of slot"<<i+1<<": "; 
     while(1) { //You must keep reading until you have read a valid value 
     cin>>value; 
     bool alreadyPresent = false;  

     for(int j=0;j<i;j++){ //You only have to check against already inserted values! 
           //Before you were checking against uninitialized values!! 
      if(value == aArray[j]) 
      { 
      alreadyPresent = true; 
      break; //I don't need to further iterate the array 
      } 

     } 

     if (alreadyPresent) 
      cout<< std::endl << value exists, please re enter: "; 
     else 
      break; //I can proceed with the next value, user has not to reenter the value 
     } 
    aArray[i] = value; 

    std::cout << std::endl; //next line... 
    } 

备选：

for(int i=0;i<arr_size;i++) 
    { 
     cout<<"enter value of slot"<<i+1<<": "; 

     bool alreadyPresent; 
     do { //You must keep reading until you have read a valid value 
     cin>>value; 
     alreadyPresent = false;  

     for(int j=0;j<i;j++){ //You only have to check against already inserted values! 
           //Before you were checking against uninitialized values!! 
      if(value == aArray[j]) 
      { 
      alreadyPresent = true; 
      cout<< std::endl << value exists, please re enter: "; 
      break; //I don't need to further iterate the array 
      } 

     } 

     } while (alreadyPresent); 
    aArray[i] = value; 

    std::cout << std::endl; //next line... 
    }