我之前张贴了这个,你需要使用的数据集,你可以调用最新的功能。看看你是否可以按照这个:SQL Server: calculating date ranges它的奇迹。具体看看For Reporting Services Folks
的部分。
对你来说将是非常简单的,如果他们选择2011/11/27并要返回11/1/2011你只需要调用它轮流调用函数MONTH_START数据集。它在该线程中都有很好的记录并广泛使用。
它的JIST是你需要在RS这样的功能:
CREATE FUNCTION [dbo].[udfCommonDates] (@date datetime)
RETURNS @t table (week_start datetime,
week_end datetime,
lastweek_start datetime,
lastweek_end datetime,
month_start datetime,
month_end datetime,
lastmonth_start datetime,
lastmonth_end datetime,
yesterday_start datetime,
yesterday_end datetime,
today_start datetime,
today_end datetime,
thisweek_monday_start datetime,
thisweek_monday_end datetime,
year_start datetime,
year_end datetime,
tomorrow_noon datetime,
today_noon datetime,
date_only datetime)
BEGIN
INSERT @t
SELECT
dbo.get_week_start (@date) AS week_start,
dbo.get_week_end (@date) AS week_end,
dbo.get_week_start (DATEADD(d, -7, @date)) AS lastweek_start,
dbo.get_week_end (DATEADD(d, -7, @date)) AS lastweek_end,
dbo.get_month_start(@date) AS month_start,
dbo.get_month_end (@date) AS month_end,
dbo.get_month_start (DATEADD(m,-1, @date)) AS lastmonth_start,
dbo.get_month_end (DATEADD(m,-1,@date)) AS lastmonth_end,
dbo.get_yesterday_start (@date) AS yesterday_start,
dbo.get_yesterday_end (@date) AS yesterday_end,
dbo.get_today_start (@date) AS today_start,
dbo.get_today_end (@date) AS today_end,
dbo.get_weekday_start(1,@date) AS thisweek_monday_start,
dbo.get_weekday_end(1,@date) AS thisweek_monday_end,
dbo.get_year_start(@date) AS year_start,
dbo.get_year_end(@date) AS year_end,
dbo.get_tomorrow_noon(@date) AS TomorrowNoon,
dbo.get_today_noon(@date) AS TodayNoon,
dbo.get_date_only(@date) AS DateOnly
RETURN
END
然后,你需要的标量值的函数为每一个:
CREATE FUNCTION [dbo].[get_date_only] (@date datetime)
RETURNS datetime
WITH SCHEMABINDING, RETURNS NULL ON NULL INPUT
AS
BEGIN
RETURN dateadd(day, DateDiff(day, 0, GetDate()), 0)
END
GO
CREATE FUNCTION [dbo].[get_month_end] (@date datetime)
RETURNS datetime
WITH SCHEMABINDING, RETURNS NULL ON NULL INPUT
AS
BEGIN
RETURN dateadd(ms, -3, dateadd (m,datediff(m,0,
dateadd(m,1,@date)),0))
END
GO
CREATE FUNCTION [dbo].[get_month_start] (@date datetime)
RETURNS datetime
WITH SCHEMABINDING, RETURNS NULL ON NULL INPUT
AS
BEGIN
RETURN dateadd(m,datediff(m,0, @date),0)
END
GO
CREATE FUNCTION [dbo].[get_today_end] (@today datetime)
RETURNS datetime
WITH SCHEMABINDING, RETURNS NULL ON NULL INPUT
AS
BEGIN
return dateadd(ms, -3, datediff(d,0,dateadd(d,1,@today)))
END
GO
CREATE FUNCTION [dbo].[get_today_noon](@date datetime)
RETURNS datetime
WITH SCHEMABINDING, RETURNS NULL ON NULL INPUT
AS BEGIN
RETURN DATEADD(hh, 12, DATEADD(d,DATEDIFF(d,0, @date),0))
END
GO
CREATE FUNCTION [dbo].[get_today_start] (@today datetime)
RETURNS datetime
WITH SCHEMABINDING, RETURNS NULL ON NULL INPUT
AS BEGIN
return dateadd(day, 0, datediff(d,0,@today))
END
GO
CREATE FUNCTION [dbo].[get_tomorrow_noon](@date datetime)
RETURNS datetime
WITH SCHEMABINDING, RETURNS NULL ON NULL INPUT
AS BEGIN
RETURN DATEADD(hh, 12, DATEADD(d,DATEDIFF(d,-1, @date),0))
END
GO
CREATE FUNCTION [dbo].[get_week_end] (@date datetime)
RETURNS datetime
WITH SCHEMABINDING, RETURNS NULL ON NULL INPUT
AS BEGIN
return dateadd(yyyy, datepart(yyyy,
dateadd(weekday,7-datepart(weekday, @date),@date))-1900, 0)
+ dateadd(ms, -3,
dateadd(dy, datepart(dy,
dateadd(weekday,7-datepart(weekday, @date),@date)),0))
END
GO
CREATE FUNCTION [dbo].[get_week_start] (@date datetime)
RETURNS datetime
WITH SCHEMABINDING, RETURNS NULL ON NULL INPUT
AS BEGIN
return dateadd(yyyy, datepart(yyyy,
dateadd(weekday,1-datepart(weekday, @date),@date))-1900, 0)
+ dateadd(dy, datepart(dy,
dateadd(weekday,1-datepart(weekday, @date),@date))-1,0)
END
GO
CREATE FUNCTION [dbo].[get_weekday_end] (@weekday tinyint,
@date datetime)
RETURNS datetime
WITH SCHEMABINDING, RETURNS NULL ON NULL INPUT
AS BEGIN
return dateadd(yyyy, datepart(yyyy,
dateadd(weekday,@weekday-
datepart(weekday, @date),@date))-1900, 0)
+ dateadd(ms, -3,
dateadd(dy, datepart(dy,
dateadd(weekday,@weekday-datepart(weekday, @date),
@date)),0))
END
GO
CREATE FUNCTION [dbo].[get_weekday_start] (@weekday tinyint,
@date datetime)
RETURNS datetime
WITH SCHEMABINDING, RETURNS NULL ON NULL INPUT
AS BEGIN
return dateadd(yyyy, datepart(yyyy,
dateadd(weekday,@weekday-
datepart(weekday, @date),@date))-1900, 0)
+ dateadd(dy, datepart(dy,
dateadd(weekday,@weekday-datepart(weekday, @date),
@date))-1,0)
END
GO
CREATE FUNCTION [dbo].[get_year_end] (@date datetime)
RETURNS datetime
WITH SCHEMABINDING, RETURNS NULL ON NULL INPUT
AS BEGIN
RETURN DATEADD(year, DATEDIFF(year, 0, GetDate())+1, 0)-1
END
GO
CREATE FUNCTION [dbo].[get_year_start] (@date datetime)
RETURNS datetime
WITH SCHEMABINDING, RETURNS NULL ON NULL INPUT
AS BEGIN
RETURN DATEADD(year,DATEDIFF(year,0, @date),0)
END
GO
CREATE FUNCTION [dbo].[get_yesterday_end] (@today datetime)
RETURNS datetime
WITH SCHEMABINDING, RETURNS NULL ON NULL INPUT
AS BEGIN
return dateadd(ms, -3, datediff(d,0,@today))
END
GO
CREATE FUNCTION [dbo].[get_yesterday_start] (@today datetime)
RETURNS datetime
WITH SCHEMABINDING, RETURNS NULL ON NULL INPUT
AS BEGIN
RETURN dateadd(day, -1, datediff(d,0,@today))
END
GO
艰苦的工作现在是报告服务完成记住一个数据集可以是一个存储过程或一个直接表。所以,你会简单地创建存储过程:
CREATE PROCEDURE [dbo].[uspCommonDates] AS
begin
set datefirst 1
declare @date datetime
set @date = getdate()
select * from dbo.udfCommonDates(@date)
end
,并使用该存储过程作为一个dataset
。所以现在你可以访问所有这些不错的日期函数。所以,你现在可以去你的参数部分,调用这些函数,像这样:
@Ken白色。你如何通过这种方式获得“高精简版”的日期?你是否像缩放代码一样缩进?仍然试图在这里学习交易的所有技巧,以最大限度地减少火焰:D谢谢! –
反斜杠(后面的撇号,与美国键盘上'〜Esc'下面的〜相同的键)围绕它们,将它们视为内联代码。 –
谢谢!当我在前面的问题中注意到这个时,我忘了问这个问题。 –