我想实现象下面这样笨的ORM所示的SQL代码(它的工作原理)同样的事情:如何在Codeigniter中使用ORM从两个表连接起来进行选择?
SELECT question.`id`,`title`,`question`,`answer` FROM answer LEFT JOIN question ON answer.question_id = question.id WHERE question.`id` = 1
我做了如下代码:
$this->db->select('question.id, question.title, question.question, answer.answer')->from('answer')->join('question', 'answer.question_id = question_id')->where('question.id',1);
$query = $this->db->get();
这是行不通的,而不是中选择question.id = 1
,它让所有的答案,这似乎是在where子句中完全不
我提供以下
的表结构0CREATE TABLE `question` (
`id` int(11) unsigned NOT NULL AUTO_INCREMENT,
`title` varchar(128) NOT NULL DEFAULT '',
`question` text NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB AUTO_INCREMENT=8 DEFAULT CHARSET=latin1;
CREATE TABLE `answer` (
`id` int(11) unsigned NOT NULL AUTO_INCREMENT,
`question_id` int(11) unsigned NOT NULL,
`answer` text NOT NULL,
PRIMARY KEY (`id`),
KEY `question_id` (`question_id`),
CONSTRAINT `answer_ibfk_1` FOREIGN KEY (`question_id`) REFERENCES `question` (`id`) ON DELETE CASCADE ON UPDATE CASCADE
) ENGINE=InnoDB AUTO_INCREMENT=13 DEFAULT CHARSET=latin1;
是否使用的是ORM? –
@raheelshan我正在使用Codeigniter构建在活动记录 – mko
@raheelshan我自己发现了这个问题,我使用数组错误 – mko