在jqGrid中显示Json数组数据

我正在开发基于Web的项目与Spring MVC，休眠& jQuery与码头服务器.. 我想显示有关JSON响应的数据。这里是控制器类的json方法。（我需要表现出港口在我的网格细节）在jqGrid中显示Json数组数据

@Entity

@Table（name = “港湾”）公共类港{

@Id 
@Column(name="HARBOUR_ID") 
@GeneratedValue 
private Integer harbourId; 

@Column(name="HARBOURCODE") 
private String harbourCode; 

@Column(name="HARBOURNAME") 
private String harbourName; 

@Column(name="STREETNO") 
private String streetNo; 

@Column(name="STREETONE") 
private String streetOne; 

@Column(name="STREETTWO") 
private String streetTwo; 

@Column(name="CITYNAME") 
private String cityName; 

@Column(name="PROVINCE") 
private String province; 

@Column(name="ALL_ID") 
private String allocationId; & Getter & Setters

&这是我的控制器类方法，用于生成json数组作为响应

@RequestMapping("/selectHarbour") 
public ModelAndView selectHarbour(Map<String, Object> map,HttpServletRequest request, 
     HttpServletResponse response) { 
    try { 

    List <Harbour> list= harbourService.listHarbour(); 
    JSONArray jsonArray=new JSONArray(); 
    for(Harbour harbour:list){ 
     JSONArray array=new JSONArray(); 
     array.put(harbour.getHarbourId()); 
     array.put(harbour.getHarbourCode()); 
     array.put(harbour.getHarbourName()); 
     array.put(harbour.getCityName()); 
     array.put(harbour.getProvince()); 
     jsonArray.put(array); 
    } 
    response.getWriter().write(jsonArray.toString()); 
    return null; 
    }catch(Exception exception){ 
     System.out.println("error is "+exception); 
    } 
    return null; 
}

最后，这是我的jquery生成jqGrid。

<td colspan="2"> 
     <!-- Insert Data Tables --> 
     <table id="list5"></table> 
     <div id="pager5"></div> 
     <br /> 
     <a href="#" id="a1">Get data from selected row</a> 
     <br /> 
    </td> 

<script type="text/javascript"> 
jQuery("#list5").jqGrid({ 
    url:'selectHarbour.html', 
      datatype: "json", 
      colNames:['Inv No','Date', 'Client', 'Amount','Tax','Total','Notes'], 
      colModel:[ 
         {name:'id',index:'id', width:55}, 
         {name:'invdate',index:'invdate', width:90}, 
         {name:'name',index:'name', width:100}, 
         {name:'amount',index:'amount', width:80, align:"right"}, 
         {name:'tax',index:'tax', width:80, align:"right"}, 
         {name:'total',index:'total', width:80,align:"right"}, 
         {name:'note',index:'note', width:150, sortable:false} 
         ], 
       rowNum:10, 
       rowList:[10,20,30], 
       pager: '#pager5', 
       sortname: 'id', 
       viewrecords: true, 
       sortorder: "desc", 
       caption:"Simple data manipulation", 
       editurl:"" 
       }).navGrid("#pager5", 
         {edit:false,add:false,del:false}); 
         jQuery("#a1").click(function(){ 
          var id = jQuery("#list5").jqGrid('getGridParam','selrow'); 
          if (id) { 
           var ret = jQuery("#list5").jqGrid('getRowData',id); 
           alert("id="+ret.id+" invdate="+ret.invdate+"..."); 
           } else { alert("Please select row");} 
          }); 
</script>

萤火虫这样表示我的反应..

[5， “CLM”， “科伦坡”， “科伦坡”， “西方”]，[ 6，“HMB”，“Hambanthota”，“Colombo 07”，“Southern”]]

然后朋友，我的错误在哪里？？？数据未显示在我的网格中

来源

2011-09-19 priyalhdp

是否需要jsonReader选项？ – priyalhdp

您的控制器需要一些修改;我假设客户发布一些在这个例子：

@SuppressWarnings("unchecked") 
@RequestMapping(value = "/selectHarbour", method = POST) 
public ResponseEntity<String> createEntity(HttpServletRequest request, @RequestBody Specialist specialist) { 
    specialistBo.save(specialist); 
    final int id = specialist.getId(); 
    URI uri = new UriTemplate("{requestUrl}/{username}").expand(request.getRequestURL().toString(), id); 
    final HttpHeaders headers = new HttpHeaders(); 
    headers.put("Location", singletonList(uri.toASCIIString())); 
    return new ResponseEntity<String>(headers, HttpStatus.CREATED); 
}

如果你想要得到的东西应该是与此类似：

@RequestMapping(method = GET) 
public 
@ResponseBody 
Page<Specialist> listEntities(@RequestParam(value = "page", required = false, defaultValue = "1") int page, 
           @RequestParam(value = "max", required = false, defaultValue = "5") int max, 
           @RequestParam(value = "sidx", required = false, defaultValue = "grid_name") String sidx, 
           @RequestParam(value = "sord", required = false, defaultValue = "desc") String sord, 
           @RequestParam(value = "filters", required = false, defaultValue = "") String filters) { 
    return specialistBo.getSpecialist(page, max, stringStringMap.get(sidx), sord, filters); 
}

@Transactional(readOnly = true) 
    public Page<Specialist> getSpecialist(int page, int max, String sidx, String sord, String filters) { 
     int count = ((Long) getSession().createQuery("select count(*) from Specialist").iterate().next()).intValue(); 
     final int start = max * page - max; 
     @SuppressWarnings("unchecked") 
     List<Specialist> list = 
       getSession().createCriteria(Specialist.class) 
         .add(Restrictions.sqlRestriction("name like '%%' order by %s %s limit %s,%s")).setResultTransformer(Criteria.DISTINCT_ROOT_ENTITY).list(); 
     return new Page<Specialist>(list, page, max, count); 
    }

@XmlRootElement 
@XmlSeeAlso({Specialist.class, Aptitude.class}) 
    public class Page<T> { 
     private List<T> rows; 
     private int page; 
     private int max; 
     private int total;

您将需要为Page创建getter和setter。希望这会有所帮助

来源

2011-12-15 22:12:35 Jaym

在jqGrid中显示Json数组数据

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