转换2只列出了进入名单

Question

的名单上有2所列出：

x = ['a','b','c'] 
y = ['d','e','f'] 

我需要列出的一个列表：

z = [['a','d'],['b','e'],['c','f']] 

我的尝试：

# Concatenate x and y with a space 
w = [] 
for i in range(len(x)): 
    w.append(x[i]+" "+y[i]) 

# Split each concatenated element into a sublist 
z = [] 
for i in range(len(w)): 
    z.append(w[i].split()) 

有直接执行此操作而不使用2 for循环的方法？ （我是很新的Python）的

Answer 1

您可以使用zip（itertools.izip如果名单是大）：

>>> x = ['a','b','c'] 
>>> y = ['d','e','f'] 
>>> zip(x, y) 
[('a', 'd'), ('b', 'e'), ('c', 'f')] 
>>> map(list, zip(x, y)) # If you need lists instead of tuples 
[['a', 'd'], ['b', 'e'], ['c', 'f']] 
>>> 

Answer 2

如果两个相同的长度，使用enumerate：

[[a,y[ind]] for ind, a in enumerate(x)] 

更效率高于zip。

In [6]: %timeit [[a,y[ind]] for ind,a in enumerate(x)] 
1000000 loops, best of 3: 970 ns per loop 

In [7]: %timeit map(list, zip(x, y)) 
1000000 loops, best of 3: 1.48 µs per loop