将csv导入到mysql数据库 - 错误

Question

我创建了一个php脚本，我将把它放到cron作业中，并且应该在午夜执行，但这不是问题。问题是当cron运行我的代码时，它删除了数据库中的所有记录，但不会从CSV文件中插入新记录。任何提示？

PHP代码如下：

<?php 

# I run this script from a cron job every night to update 
# the mysql database I use with my employee web site 
# so it matches my local database every day. Feel free to 
# modify it to meet your specific needs. If you find it 
# usefull, drop me an email and let me know. 

# edit the follow six items to use the script 

# first connect to your mysql database 
# i have my connection settings in a diferent file 
# so i just include that file in all my scripts 
include("db.php"); 

# assign the tables that you want to import to to the table array 
$table = array( 
       'table1', 
       'table2', 
       'table3', 
       'table4', 
       'table5', 
     ); 

# if the first row of your csv file contains column headings: 
# $columnheadings=1 
# if the first row does not contain column headings and should be imported: 
# $columnheadings=0 
$columnheadings = 0; 

# contains the email address you want the results sent to 
$emailaddress = "user@domain.com"; 

# contains the subject you want the message to have 
$subject = "Enter Subject Here"; 

# contains the email address that will show in the from line 
$emailfrom = "user@domain.com"; 

# perform the required operations for every table listed in the table array 
foreach ($table as $tablename) { 

    # empty the table of its current records 
    $deleterecords = "TRUNCATE TABLE `$tablename`"; 
    mysql_query($deleterecords); 

    # intialize your counters for successful and failed record imports 
    $pass = 0; 
    $fail = 0; 

    # the csv file needs to be the same name as the table, 
    # comma seperated with the columns in the same order as the table, 
    # and in the same dir as this script 
    $filecontents = file ("$tablename.csv"); # .csv is added to the table name to get the name of the csv file 

    # every record in the csv file will be inserted into the table unless an error occurs with that record 
    for($i=$columnheadings; $i<sizeof($filecontents); $i++) { 
     $insertrecord = "Insert Into `$tablename` Values ($filecontents[$i])"; 
     mysql_query($insertrecord); 
     if(mysql_error()) { 
      $fail += 1;  # increments if there was an error importing the record 
     } 
     else 
     { 
      $pass += 1;  # increments if the record was successfully imported 
     } 
    } 

    # adds a line to the email message we will send stating how many records were imported 
    # and how many records failed for each table 
    $message .= "Table $tablename: Success=$pass Failure=$fail \n"; 
} 

# set to the date and time the script was run 
$runtime = (date("d M Y H:i")); 

# add the run time to the body of the email message 
$message .= "\nTime of the message: $runtime (server time zone)\n\n"; 

# Send the email message 
mail($emailaddress, $subject, $message, "From: '$emailfrom'"); 

?> 

Answer 1

请告诉我表的模式，而你在最后得到的$message什么？你是否获得所有行失败？

补充：

由于所有行失败，意味着在INSERT语句的一些问题，或者可能是CSV和目标表之间的架构不匹配。试试这个

# and in the same dir as this script 
    $filecontents = file ("tablename.csv"); # .csv is added to the table name to get the name of the csv file 

    # every record in the csv file will be inserted into the table unless an error occurs with that record 
    for($i=$columnheadings; $i<sizeof($filecontents); $i++) { 
     $insertrecord = "Insert Into `$tablename` Values ($filecontents[$i])"; 
     mysql_query($insertrecord); 
     if(mysql_error()) { 
      $fail += 1;  # increments if there was an error importing the record 
      //this is include exact error in email, and will help you to identify the 
      //problem very easily. 
      $message .= mysql_errno() . ": " . mysql_error() . "\n"; 
     } 
     else 
     { 
      $pass += 1;  # increments if the record was successfully imported 
     } 
    } 

试试这个，让我知道你的发现？

Answer 2

你的代码没有检查文件的存在 - 那么，如果它不在你想要的位置呢？根据你如何从cron运行它，它可能从不同的目录运行，如果你从网上运行它。