我刚刚完成了对本文的练习,并想知道是否可以使用相同的技术(字典,if语句等等)更有效地完成此操作。代码效率低下。为绝对初学者编程的Python:第5章挑战#2
挑战如下: 编写角色扮演游戏的角色造物主程序。玩家应该获得30点的资源,用于四个属性:力量,健康,智慧和敏捷。玩家应该能够在任何属性上从池中消费点数,并且还应该能够从属性获得积分并将其放回池中。
链接:http://pastebin.com/PeLLz83e
我刚刚完成了对本文的练习,并想知道是否可以使用相同的技术(字典,if语句等等)更有效地完成此操作。代码效率低下。为绝对初学者编程的Python:第5章挑战#2
挑战如下: 编写角色扮演游戏的角色造物主程序。玩家应该获得30点的资源,用于四个属性:力量,健康,智慧和敏捷。玩家应该能够在任何属性上从池中消费点数,并且还应该能够从属性获得积分并将其放回池中。
链接:http://pastebin.com/PeLLz83e
一,你可以很容易地改善的是,第一个系列“如果是:
if pts2 == "1":
skills["Strength"] += pts
points -= pts
...
通过使用字典skills_dict = {"1": "Strength", "2": "Health", ... }
,你可以这样做:
skills[skills_dict[pts2]] += pts
points -= pts
同对于第二组'如果的
那么,一个在你的代码看起来不太优雅的方式是,有很多非常相似的序列,具体是:
if rmv2 == "3":
if rmv < skills["Dextarity"]:
skills["Dextarity"] -= rmv
points += rmv
else:
print("No")
如果这一变化的唯一的事情是什么输入,真是静被修改,以及是否要添加或删除一个值。如果你找到一种方法将它变成一个可重用组件,就像使用一个函数一样,你可以让你的代码看起来更好一些。
一些评论:
points=int(30)
30已经是一个int。更改为
points=30
而且
while player != "e":
大概应该是:
while selection != "exit"
我了拆分此程序为小功能负荷,使一类的字符来存储技能和剩余点。
我认为你正在寻找这样的东西。函数在第5章中没有解释,所以我没有包含任何函数。
# role playing program
#
# spend 30 points on strenght, health, wisdom, dexterity
# player can spend and take points from any attribute
# library contains attribute and points
attributes = {"strenght": int("0"),
"health": "0",
"wisdom": "0",
"dexterity": "0"}
pool = int(30)
choice = None
print("The Making of a Hero !!!")
print(attributes)
print("\nYou have", pool, "points to spend.")
while choice != "0":
# list of choices
print(
"""
Options:
0 - End
1 - Add points to an attribute
2 - remove points from an attribute
3 - Show attributes
"""
)
choice = input("Choose option: ")
if choice == "0":
print("\nYour hero stats are:")
print(attributes)
print("Good-Bye.")
elif choice == "1":
print("\nADD POINTS TO AN ATTRIBUTE")
print("You have", pool, "points to spend.")
print(
"""
Choose an attribute:
strenght
health
wisdom
dexterity
"""
)
at_choice = input("Your choice: ")
if at_choice.lower() in attributes:
points = int(input("How many points do you want to assign: "))
if points <= pool:
pool -= points
result = int(attributes[at_choice]) + points
attributes[at_choice] = result
print("\nPoints have been added.")
else:
print("\nYou do not have that many points to spend")
else:
print("\nThat attribute does not exist.")
elif choice == "2":
print("\nREMOVE POINTS FROM AN ATTRIBUTE")
print("You have", pool, "points to spend.")
print(
"""
Choose an attribute:
strenght
health
wisdom
dexterity
"""
)
at_choice = input("Your choice: ")
if at_choice.lower() in attributes:
points = int(input("How many points do you want to remove: "))
if points <= int(attributes[at_choice]):
pool += points
result = int(attributes[at_choice]) - points
attributes[at_choice] = result
print("\nPoints have been removed.")
else:
print("\nThere are not that many points in that attribute")
else:
print("\nThat attribute does not exist.")
elif choice == "3":
print("\n", attributes)
print("Pool: ", pool)
else:
print(choice, "is not a valid option.")
input("\n\nPress the enter key to exit.")
这可能更适合http://codereview.stackexchange.com/ – 2011-01-30 22:06:03
是的。 Codereview是一个伟大的匹配。 – 2011-01-31 10:47:29
user596100:这里说“谢谢”的方式是upvote。就这样你知道。 :) – 2011-01-31 10:48:23