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我想干这个代码。我似乎无法弄清楚如何。如何干这个红宝石代码
def get_all_verb_nodes
all_verb_nodes = @all_nodes_ins_del_nodes.select { |node|
previous_node = node.xpath('preceding-sibling::w:r').last
base_word = previous_node.text.split.last.strip.delete('.!?,:') if previous_node
words = get_node_text(node)
next_node = node.next_element
next_node_is_insert_or_delete = is_insert_or_delete?(next_node.name) if next_node
next_node_word = next_node.text.strip if next_node
words.length <= 2 && words.any? { |word| is_a_verb?(base_word+word) || is_a_verb?(word) && !is_pluralized?(base_word+word, base_word+next_node_word) } && !next_node_is_insert_or_delete
}
end
def get_all_article_nodes
all_article_nodes = @all_nodes_ins_del_nodes.select { |node|
previous_node = node.xpath('preceding-sibling::w:r').last
base_word = previous_node.text.split.last.strip.delete('.!?,:') if previous_node
words = get_node_text(node)
next_node = node.next_element
next_node_is_insert_or_delete = is_insert_or_delete?(next_node.name) if next_node
next_node_word = next_node.text.strip if next_node
words.length <= 2 && words.any? { |word| @articleset.include?(word) || (@articleset.include?(base_word) if word == 'n') } && [email protected]?(next_node_word) && !next_node_is_insert_or_delete
}
end
两者几乎相同,只是最后一行定义了函数的具体要求。
任何想法赞赏。
它看起来相当程序化,很难阅读评论,但块和调用'yield'可能是你在这里需要的。 –