如何定义一个具有相同值的多个子字典的Python字典？

我想创建一个Python dict其成员本身dict秒，他们两个是一样的：如何定义一个具有相同值的多个子字典的Python字典？

servers = { 
    "test": { 
    "auth_token": "some-auth-token", 
    "client_id": "some-client-id", 
    "client_secret": "some-client-secret", 
    "scope": "some-scope" 
    }, 
    "live": { 
    "auth_token": "auth-token-for-live", 
    "client_id": "client-id-for-live", 
    "client_secret": "client-secret-for-live", 
    "scope": "scope-for-live" 
    }, 
    "demo": servers["test"] # this doesn't work, but this is what I need 
}

我demo服务器定义是一样的我test服务器定义，但我不希望不得不重复一遍 - 有没有办法做到这一点？

来源

2017-03-09 code-tinkerer

在一条语句中无法 – timgeb

让我们做一些改变，我的演示配置=>'服务器[“示范”] [“client_secret”] =“foo'' =>进入的堆栈溢出问题，”我的测试服务器突然失败而没有改变，为什么？“我真的不认为复制粘贴是一件坏事。 – polku

你能先用测试和活键创建字典吗？然后，只需更新与演示作为关键字和测试为值例如：'servers.update（{'demo'：servers ['test']}）' –

x = { 
    "auth_token": "some-auth-token", 
    "client_id": "some-client-id", 
    "client_secret": "some-client-secret", 
    "scope": "some-scope" 
} 

servers = { 
    "test": x, 

    "live": { 
    "auth_token": "auth-token-for-live", 
    "client_id": "client-id-for-live", 
    "client_secret": "client-secret-for-live", 
    "scope": "scope-for-live" 
    }, 

    "demo": x 

}

例如， https://repl.it/GO6Y/0

来源

2017-03-09 16:28:03 TessellatingHeckler

是的，当然我可以做到这一点;我想知道在“服务器”本身的定义中是否有办法做到这一点。 –

“我该如何做X？” “像这样”“当然就是这样，我实际上是在问一个不同的问题，但保持它的秘密，因为原因” – TessellatingHeckler

servers = { 
    "test": { 
    "auth_token": "some-auth-token", 
    "client_id": "some-client-id", 
    "client_secret": "some-client-secret", 
    "scope": "some-scope" 
    }, 
    "live": { 
    "auth_token": "auth-token-for-live", 
    "client_id": "client-id-for-live", 
    "client_secret": "client-secret-for-live", 
    "scope": "scope-for-live" 
    }} 

servers['demo'] = servers['test']

来源

2017-03-09 16:29:07 harryscholes

请注意，更改为“测试”会自动更新“演示”，反之亦然。 – CaptainKinematics

如何定义一个具有相同值的多个子字典的Python字典？

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