无法访问Tastekid的API。它说错误：403（请求禁止）

Question

我无法运行代码来读取Tastekid的API（python），它说错误：403（请求禁止）但是我可以访问相同的浏览器中的URL。 对钥匙也一样。

请找到下面的查询

from urllib2 import Request, urlopen, URLError 
req = Request('http://www.tastekid.com/api/similar?q=red+hot+chili+peppers%2C+pulp+fiction') 
try: 
    response = urlopen(req) 
except URLError as e: 
    if hasattr(e, 'reason'): 
     print 'We failed to reach a server.' 
     print 'Reason: ', e.reason 
    elif hasattr(e, 'code'): 
     print 'The server couldn\'t fulfill the request.' 
     print 'Error code: ', e.code 
else: 
    'everything is fine' 

Answer 1

您需要发出请求的url

headers = { 'User-Agent' : "Mozilla/4.0 (compatible; MSIE 5.5; Windows NT)" }  
req = Request('http://www.tastekid.com/api/similar?q=red+hot+chili+peppers%2C+pulp+fiction', headers = headers) 

---

这里头内的User-Agent键被设定为前加适量headers告诉服务器我们正在从浏览器而不是程序发出请求

测试

• 文件名test.py

  from urllib2 import Request, urlopen, URLError 
  
  #Changes made in the below two line 
  
  headers = { 'User-Agent' : 'Mozilla/4.0 (compatible; MSIE 5.5; Windows NT)' } 
  req = Request('http://www.tastekid.com/api/similar?q=red+hot+chili+peppers%2C+pulp+fiction', headers = headers) 
  
  
  try: 
      response = urlopen(req) 
  except URLError as e: 
      if hasattr(e, 'reason'): 
       print 'We failed to reach a server.' 
       print 'Reason: ', e.reason 
      elif hasattr(e, 'code'): 
       print 'The server couldn\'t fulfill the request.' 
       print 'Error code: ', e.code 
  else: 
      print 'everything is fine' 
  

• 无头

  $ python test.py 
  We failed to reach a server. 
  Reason: Forbidde 
  

• 页眉

  $ python test.py 
  everything is fine