2017-10-29 43 views
-1
$.ajax({ 
      url: "salvar.php", 
      type: "post", 
      async: false, 
      dataType : "html", 
      data: { 
       "feito": 1, 
       "id": id, 
       "html": html, 
       "css": css, 
       "js": js 
      }, 
      success: function(data) { 
       alert(data.id); 
      } 
     }); 

我正在使用下面的代码在ajax中发送数据到php页面做与数据库一起处理。获取php id与ajax?

<?php 

require_once 'banco/conexao.php'; 

if(isset($_POST['feito'])){ 
    $id_setado = $_POST["id"]; 
    if($id_setado === ''){ 
     $id = base_convert(time(), 10, 36); 
     $busca = mysqli_query($conn,"SELECT id FROM codigos WHERE id = '$id'"); 
     $buscaId = mysqli_fetch_array($busca); 
     if ($buscaId == false) { 
      $html = base64_encode($_POST['html']); 
      $css = base64_encode($_POST['css']); 
      $js = base64_encode($_POST['js']); 
      $inserir = mysqli_query($conn,"INSERT INTO codigos (id,html,css,js) VALUES ('$id','$html','$css','$js')"); 
     }  
    }else{ 
     $id = $id_setado; 
     $html = base64_encode($_POST['html']); 
     $css = base64_encode($_POST['css']); 
     $js = base64_encode($_POST['js']); 
     $atualizar = mysqli_query($conn,"UPDATE codigos SET html='$html',css='$css',js='$js' WHERE id = '$id'"); 
    } 
} 

>

我想是知道我怎样才能得到它接受base_convert(时间(),10,36)在$ ID?;在ajax的“成功”回应中。特别是我想要的这些数据。我怎样才能得到这个PHP变量与Ajax?

+1

你的价值呼应出来。 –

+0

完美谢谢。 – Gabriel

回答