MySQL的计数和group by

Question

天

我有以下结构

ID DATE(DATETIME)   TID 
1  2012-04-01 23:23:23 8882 

我想在每个月的每一天匹配TID = 8882

感谢数行，他们团的量

Answer 1

您可以使用DAY功能组：

SELECT DAY(Date), COUNT(*) 
FROM table 
WHERE TID = 8882 
GROUP BY DAY(Date) 

Answer 2

试试这个：

SELECT DAY(date) AS `DAY`, COUNT(1) AS `COUNT` FROM 
table1 
    WHERE TID = 8882 
GROUP BY DAY(date) 

什么MySQL Query GROUP BY day/month/year

Answer 3

不知道到底你在当月的一天是什么意思 - 你想组二月与3月1日第一次？或者你只是说日期？假如是后者，这个怎么样：

SELECT DATE(date) as d,count(ID) from TABLENAME where TID=8882 GROUP by d; 

Answer 4

尝试此查询：

SELECT COUNT(id), DAY(dat), MONTH(dat), YEAR(dat) 
FROM table 
WHERE TID=8882 
GROUP BY YEAR(dat), MONTH(dat), DAY(dat);