显示实际的对象我有一个模型认定中,如下所示:Django的:如何在管理
class Artist(models.Model):
"""Model class to record Artist"""
artist_name = models.CharField(max_length=200)
artist_id = models.CharField(unique=True, max_length=50)
# similar relationship is defined.
related_to = models.ManyToManyField("self", null=True, blank=True)
def __unicode__(self):
return self.artist_name
当我使用Django的管理面板“删除”为艺术家管理行动,我得到:
Artist: trojan
From_artist-to_artist relationship: Artist_related_to object
From_artist-to_artist relationship: Artist_related_to object
From_artist-to_artist relationship: Artist_related_to object
From_artist-to_artist relationship: Artist_related_to object
Artist: betty
From_artist-to_artist relationship: Artist_related_to object
From_artist-to_artist relationship: Artist_related_to object
我如何得到我在删除过程中发出警告的实际关系?
换句话说,如何将'Artist_related_to object'人性化以反映真实的艺术家姓名。
我不觉得你尝试过什么,我给关于这个问题,尝试,然后回复它不工作ü图片的方式。 – 2013-05-02 09:52:24