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搜索一个数组 - 我发现下面这个函数用于搜索一个对于单个字符串“很好”的数组,它将匹配数组值和/或数组值,并匹配数组中的键,但是我真正想要做的只是匹配满足/返回所有搜索值的数组。该查询示例可以返回任何匹配的记录 - search1或serach2不匹配,其中搜索条件search1和serach2都满足。从数组中搜索和匹配
例如阵列
array 1 - key1=>search1,key2=>search2,key3=>search3,key4=>search4
array 2 - key1=>search2,key2=>search1,key3=>search4,key4=>search2
array 3 - key1=>search3,key2=>search2,key3=>search4,key4=>search1
array 4 - key1=>search1,key2=>search3,key3=>search2,key4=>search4
所以如果你跑了功能这些阵列(上图)它应该只匹配阵列1,因为只有阵列1已经搜索和关键字相匹配。尽管array4与key1的搜索匹配,但它不应该被返回,因为它不匹配key2的搜索,就像明智的array3一样,因为它只能在key2上匹配。
建议&请帮忙。
function recursiveArraySearch($haystack, $needle, $index = null) {
$aIt = new RecursiveArrayIterator($haystack);
$it = new RecursiveIteratorIterator($aIt);
while($it->valid()) {
if(((isset($index) AND ($it->key() == $index)) OR (!isset($index))) AND ($it->current() == $needle)) {
return $aIt->key();
}
$it->next();
}
return false;
}
$sql = mysql_query("SELECT * FROM atable WHERE tableID = '1' ");
while($row = mysql_fetch_array($sql)):
$content = json_decode($row['tosearch']);
echo recursiveArraySearch(json_decode($row['tosearch']), 'search1','key1');
echo recursiveArraySearch(json_decode($row['tosearch']), 'search2','key2');
endwhile;
该函数的“理想”的格式将是这样的:
echo recursiveArraySearch(json_decode($row['tosearch']),
array('search1'=>'key1'),array(('search2'=>'key2'));