读取输入文件，插入文本输出文件

Question

我有一个名为“namelist.txt”与电子邮件地址输入文件：

user1@domain.com 
user2@domain.com 
user3@domain.com 

我试图读取该输入文件中的地址，将其价值的应该读输出文件（newfile.txt）：

user "user1@domain.com" with pass"pass" is "user1@domain.com" here 
user "user2@domain.com" with pass"pass" is "user2@domain.com" here 
user "user3@domain.com" with pass"pass" is "user3@domain.com" here 

我来最接近的是用awk：

awk '{print "user $0 there with pass"pass" is user $0 here"}' <namelist.txt> newfile.txt 

然而，这打印如下：

user $0 there with pass is user $0 here 
user $0 there with pass is user $0 here 
user $0 there with pass is user $0 here 

这不打印变量值，也不是“通”值。

我不知道我错了，还是我甚至在正确的轨道，所以任何意见和/或指针将不胜感激。

编辑：

使用：

awk '{print "user \""$0"\" there with pass \"pass\" is user \""$0"\" here}' file 

导致在Ubuntu（14.04.2 LTS）以下输出：

“heree与通 ”合格“ 是用户” USER1 @ domain.com
“heree with pass”pass“is user”user2@domain.com
“heree with pass”pass“is user”user3@domain.com

上述代码工作正常在UNIX终端而不在Ubuntu也不树莓裨。

我很困惑，为什么发行版之间的差异。

Answer 1

的$变量需要报价之外，你需要逃避你想看到的报价。

awk '{print "user \""$0"\" there with pass\"pass\" is user \""$0"\" here"}' file 

user "user1@domain.com" there with pass"pass" is user "user1@domain.com" here 
user "user2@domain.com" there with pass"pass" is user "user2@domain.com" here 
user "user3@domain.com" there with pass"pass" is user "user3@domain.com" here 

Answer 2

将数据输入到输出的一些格式的字符串时，您已经包含文字字符串内，但在任何情况下，文本$0，它通常是最清晰和最容易在将来提高，如果你使用printf代替print：

$ awk '{printf "user \"%s\" there with pass \"pass\" is user \"%s\" here\n", $0, $0}' file 
user "user1@domain.com" there with pass "pass" is user "user1@domain.com" here 
user "user2@domain.com" there with pass "pass" is user "user2@domain.com" here 
user "user3@domain.com" there with pass "pass" is user "user3@domain.com" here 

并且不使用awk输入重定向，因为这会删除脚本访问输入文件名的能力。 awk完全有能力打开文件本身。