IOS的UIImagePickerController不工作

-3

UIImagePickerController *imagePicker = [[UIImagePickerController alloc] init] ; 
[imagePicker setAllowsEditing:YES] ; 
[imagePicker setDelegate:self] ; 
[imagePicker setMediaTypes:[NSArray arrayWithObjects:(NSString *)kUTTypeImage, nil]] ; 
[imagePicker setSourceType:UIImagePickerControllerSourceTypePhotoLibrary] ; 
[self presentViewController:imagePicker animated:YES completion:nil] ;

来源

2015-05-19 anoop jha

用适当的格式发布您的问题。 –

您可以添加输出控制台吗？什么是错误？ – thedjnivek

第1步：添加委托

@interface APPViewController : UIViewController <UIImagePickerControllerDelegate, UINavigationControllerDelegate>

第2步：初始化UIImagePicker上点击按钮动作

- (IBAction)selectPhoto:(UIButton *)sender { 

    UIImagePickerController *picker = [[UIImagePickerController alloc] init]; 
    picker.delegate = self; 
    picker.allowsEditing = YES; 
    picker.sourceType = UIImagePickerControllerSourceTypePhotoLibrary; 
    [self presentViewController:picker animated:YES completion:NULL];  
}

第3步：

- (void)imagePickerController:(UIImagePickerController *)picker didFinishPickingMediaWithInfo:(NSDictionary *)info { 

    UIImage *chosenImage = info[UIImagePickerControllerEditedImage]; 
    self.imageView.image = chosenImage; 
    [picker dismissViewControllerAnimated:YES completion:NULL]; 
}

第4步：关闭控制器

- (void)imagePickerControllerDidCancel:(UIImagePickerController *)picker 
{  
     [picker dismissViewControllerAnimated:YES completion:NULL];  
}

注意：您发布的细节描述问题

来源

2015-05-19 07:11:52 Ramdy

您正在使用的UIImagePickerController作为变量而不是作为一个属性或特性，这意味着将在您的函数结束时被释放。将您的UIImagePickerController设置为属性或属性，然后该委托将工作。

来源

2015-12-30 11:02:32

如果您使用的是UIPopoverPresentationController，请确保在呈现imagePicker之前关闭弹出窗口。否则，它不会显示。

来源

2017-01-27 18:38:36

IOS的​​UIImagePickerController不工作

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IOS的UIImagePickerController不工作