我开始在linux上做pthread编程,并且在第一个程序中我完全搞不懂。下面是我正在运行的程序linux上的pthread执行
#include <stdio.h>
#include <stdlib.h>
#include <pthread.h>
void *print_message_function(void *ptr);
int main(){
pthread_t thread1, thread2;
char *message1 = "Thread 1";
char *message2 = "Thread 2";
int iret1, iret2;
/* Create independent threads each of which will execute function */
iret1 = pthread_create(&thread1, NULL, print_message_function, (void*) message1);
iret2 = pthread_create(&thread2, NULL, print_message_function, (void*) message2);
/* Wait till threads are complete before main continues. Unless we */
/* wait we run the risk of executing an exit which will terminate */
/* the process and all threads before the threads have completed. */
pthread_join(thread1, NULL);
printf("amit");
pthread_join(thread2, NULL);
printf("Thread 1 returns: %d\n",iret1);
printf("Thread 2 returns: %d\n",iret2);
exit(0);
}
void *print_message_function(void *ptr){
char *message;
message = (char *) ptr;
printf("%s \n", message);
}
我想知道的第一件事是线程执行的顺序是不连续的?
第二件事是我intelectally把印刷(“阿米特”);看到main在thread1终止时真的停止了,但是在输出中我们可以看到的是printf语句首先被执行。整个过程的输出是
线程1
线程2
amitThread 1返回:0
线程2返回:0
”是线程执行顺序不是顺序的“。这是正确的。如果你发现这里有足够的惊喜,请离开代码并找到一本书的多线程编程。请一路阅读本书。在编写更多或更少的随机代码之前,您可能会寻找一个好的教程。这个问题相当复杂,而不是偶然探索的东西。 https://computing.llnl.gov/tutorials/pthreads/ – 2011-02-14 11:15:50
这真的是输出?它输出`ajay`而不是`amit`?你有什么问题? – Falmarri 2011-02-14 11:16:37
对不起amit不ajay – 2011-02-14 11:17:30