这回undefined
,即使var roommate
包含正确的值:为什么AJAX响应返回undefined?
JS
roommate = $("#roommate").val();
$.post('roommateSearch.php', 'val=' + $(roommate).val(), function (response) {
alert(response);
});
roommateSearch.php
<?php
$roommate = $_POST['val'];
echo "I got your value!".$roommate;
?>
啊!当然。我觉得自己像个白痴。这工作。我会在5分钟内将答案标记为正确(声誉限制)。谢谢! – radleybobins 2011-12-23 01:26:45