2013-03-28 200 views

回答

1

转换在字符串中没有当天的名称。删除它然后铸造datetime:

declare @dateString varchar(50) 
set @dateString = 'wednesday, january 16, 2013' 

declare @index int 
set @index = charindex(',', @dateString) 
set @dateString = substring(@dateString, @index + 1, len(@dateString) - @index) 

select cast(@dateString as datetime) 
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