查找匹配或不匹配的两个表

Question

我是新来的sql所以让我道歉，我开始之前之间。

我试图国旗我会拨打以下方式保单号码相匹配。

Select c.last_name, c.first_name, c.sex, c.date_of_birth, c.record_nbr, 
case when ph.policy_nbr = cp.policy_nbr then ph.policy_nbr else 'No Match' 

From table ph 

Left join client c 
On ph.last_name = c.last_name 
And ph.first_name = c.first_name 
And ph.date_of_birth = c.date_of_birth 
And ph.sex = c.sex 
Left join person_payer cp 
On c.person_id = cp.person_id 

Group by c.last_name, c.first_name,c.date_of_birth, 
c.sex,ph.policy_num, cp.policy_nbr 

这个想法是根据姓氏，名字，dob和性别找到匹配表。然后我想验证一个保单号上的匹配或不匹配。患者记录中是否存在保单编号？不幸的是，由于客户记录中存在多个保单编号，因此这会产生匹配并且不匹配。我如何才能在报告列表中列出客户一次且仅列出“不匹配”或匹配保单编号。

Answer 1

假设策略表的名字是PolicyTable（因为它的命名表，但SQL Server的抱怨吧），你可以做选择的单柱，而不是加入。

Select c.last_name, c.first_name, c.sex, c.date_of_birth, c.record_nbr, 
ISNULL((Select top 1 ph.policy_nbr from PolicyTable ph where ph.last_name = c.last_name 
And ph.first_name = c.first_name 
And ph.date_of_birth = c.date_of_birth 
And ph.sex = c.sex 
And cp.policy_nbr = ph.policy_nbr), 'No Match') as PolicyNumber 

From client c 
Left join person_payer cp On c.person_id = cp.person_id 

Answer 2

Select c.last_name, c.first_name, c.sex, c.date_of_birth, c.record_nbr, 
isnull(cp.policy_nbr, 'No Match') 

From table ph 

Left join client c 
On ph.last_name = c.last_name 
And ph.first_name = c.first_name 
And ph.date_of_birth = c.date_of_birth 
And ph.sex = c.sex 
Left join person_payer cp 
On c.person_id = cp.person_id 
and ph.policy_nbr = cp.policy_nbr 

Group by c.last_name, c.first_name,c.date_of_birth, 
c.sex,ph.policy_num, cp.policy_nbr