阅读JSON数据带有PHP令牌

Question

如何使用PHP读取JSON数据响应？

这是代码：

$response = Unirest\Request::get("https://montanaflynn-spellcheck.p.mashape.com/check/?text=This+sentnce+has+some+probblems.", 
    array(
    "X-Mashape-Key" => "MY X-Mashape-Key", 
    "Accept" => "application/json" 
) 
); 

，并给我这个JSON数据：

{ 
    "original": "This sentnce has some probblems.", 
    "suggestion": "This sentence has some problems.", 
    and ... 
} 

我想在URL返回 “suggestion” 与$

这是一个例子：

$user_id = '123456789' 
$mytext = '?' // I WANT RETURN "suggestion" HERE ! 

$url = 'https://api.telegram.org/mytoken/sendMessage?chat_id='.$user_id.'&text='.$mytext 
file_get_contents($url); 

Answer 1

您可以使用json_decode（）。

参见： http://php.net/manual/en/function.json-decode.php

你只需要做：

$response = json_decode($response,1); 
echo $response['suggestion']; 

设置json_decode的）到1（真）的第二个参数（将返回JSON数据的关联数组。

如果你想用你的代码示例，包括它的URL：

$user_id = '123456789' 
$json = json_decode($response,1); 
$mytext = $json['suggestion']; 

$url = 'https://api.telegram.org/mytoken/sendMessage?chat_id='.$user_id.'&text='.$mytext 
file_get_contents($url); 

Answer 2

使用json_decode将json_response转换为array.Add第二个参数'true'使其成为您应该熟悉的数组。

通过指定访问建议变量。

$response = Unirest\Request::get("https://montanaflynn-spellcheck.p.mashape.com/check/?text=This+sentnce+has+some+probblems.", 
    array(
    "X-Mashape-Key" => "MY X-Mashape-Key", 
    "Accept" => "application/json" 
) 
); 
$data=json_decode($response,true); 
$url = 'https://api.telegram.org/mytoken/sendMessage?chat_id='.$user_id.'&text='.$data['suggestion']; 
echo $url;