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我正在用PHP代码创建MYSQLi表,但它返回语法错误。使用ID auto_increment创建MySQLi表返回语法错误
<?php
require_once('../connect.php');
$dbc = mysqli_connect(DB_HOST, DB_USER, DB_PASSWORD, DB_NAME);
$query = "CREATE TABLE email_list (
id INT AUTO_INCREMENT,
first_name varchar(20),
last_name varchar(20),
email varchar(60),
PRIMARY_KEY (id));";
if (mysqli_query ($dbc, $query)) {
echo "The query was successfully executed!<br />";
} else {
echo "The query could not be executed!" . mysqli_error($dbc);
}
mysqli_close($dbc);
?>
错误:
The query could not be executed!You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '(
id
))' at line 6
有机磷农药。谢谢。一旦允许,我会标记它解决。 –