0
<!DOCTYPE html>
<html>
<head>
<meta charset="UTF-8">
<title>Insert title here</title>
<script src = "A1P1Q1.js"></script>
</head>
<body>
<p id="a"></p>
<p id="firstname"></p>
<p id="details"></p>
<script>
variable();
</script>
JavaScript代码当我分离JavaScript和HTML文件,仅年龄显示
function variable(){
age = 24;
var fname = "sachin";
lname = "hunur";
details = [age, fname, lname];
document.getElementById("a").innerHTML = "the age is" +" " +age;
document.getElementById("firstname").innerHTML = "first name is" +
" " + fname;
document.getElementById("details").innerHTML = "The user details are" +
"age : " + details[0] + "first name : " + details[1] + " last name : "
+ details[2];
return;
}
块引用:所示的输出是仅: 年龄为24
如何获得印刷的名字和详细信息?
是否有在JavaScript控制台中的任何错误? – Barmar
这听起来像是在显示第一个输出后出现错误。 – Barmar
它适用于我:http://jsfiddle.net/barmar/9ndt0gLt/ – Barmar