通过PIL绘制无需裁剪的文本图像

Question

我想通过使用PIL来绘制文本。但我的问题是我需要运行程序后再次裁剪文本图像。我需要的只是文本，没有边界。任何人都可以建议？ 谢谢。 这是我的代码：

import Image, ImageDraw, ImageFont 
def draw (text, size, color) : 
    fontPath = '/home/FreeSansBold.ttf' 
    font = ImageFont.truetype(fontPath, size) 
    size2 = font.getsize(text) 
    im = Image.new('RGBA', size2, (0, 0, 0, 0)) 
    draw = ImageDraw.Draw(im) 
    draw.text((0, 0), text, font=font, fill=color) 
    im.save(text +'.png') 

drawA = draw('A', 200, 'green') 
drawC = draw('C', 200, 'blue') 
drawG = draw('G', 200, 'yellow') 
drawT = draw('T', 200, 'red') 

Answer 1

你能说清楚你的意思是没有边界吗？你想对文字边缘进行紧缩吗？如果是的话这应该工作：

import Image, ImageDraw, ImageFont 

def draw (text, size, color) : 
    fontPath = '/home/FreeSansBold.ttf' 
    font = ImageFont.truetype(fontPath, size) 
    size2 = font.getsize(text)  
    im = Image.new('RGBA', size2, (0, 0, 0, 0)) 
    draw = ImageDraw.Draw(im) 
    draw.text((0, 0), text, font=font, fill=color) 

    pixels = im.load() 
    width, height = im.size 
    max_x = max_y = 0 
    min_y = height 
    min_x = width 

    # find the corners that bound the letter by looking for 
    # non-transparent pixels 
    transparent = (0, 0, 0, 0) 
    for x in xrange(width): 
     for y in xrange(height): 
      p = pixels[x,y] 
      if p != transparent: 
       min_x = min(x, min_x) 
       min_y = min(y, min_y) 
       max_x = max(x, max_x) 
       max_y = max(y, max_y) 
    cropped = im.crop((min_x, min_y, max_x, max_y)) 
    cropped.save(text +'.png') 

drawA = draw('A', 200, 'green') 
drawC = draw('C', 200, 'blue') 
drawG = draw('G', 200, 'yellow') 
drawT = draw('T', 200, 'red') 

它产生这样的图像（我填写在红色的透明像素来显示图像更好的边界：http://img43.imageshack.us/img43/3066/awithbg.png