因此,我正在使用AFNetworking 2.0(带桥接头的ObjC框架)在本地服务器上发出一些请求。我遵循几个教程来使用Swift进行编码。这是代码:iOS Swift:使用AFNetworking分析响应json
var success = { (operation:AFHTTPRequestOperation!, response:AnyObject!) -> Void in
println(response.description)
successBlock(result:response.description)
}
var failure = { (operation:AFHTTPRequestOperation!, response:NSError!) -> Void in
println(response.description)
errorBlock(error:response.description)
}
var manager = AFHTTPRequestOperationManager()
manager.responseSerializer = AFJSONResponseSerializer();
manager.GET("http://127.0.0.1:8080/api/manufacturer", parameters: nil, success: success, failure: failure)
它检索json并成功打印它。响应是这样的:
(
{
"_id" = 539f0973e3c7f4ab1f6078f5;
name = Manufacturer01;
},
{
"_id" = 539f18c5e3c7f4ab1f6078f6;
name = Manufacturer02;
}
)
但是,我无法分析它...我想response[0]
拿到的第一个元素,但是当我尝试做它崩溃的模拟器,甚至Xcode6:(lldb) > po response[0]
。我尝试了一切,我看到的每个示例都解释了如何打印结果,但没有解释每个字段。
的response
对象看起来是这样的,当我尝试调试它:
value = Some {
Some = (instance_type = Builtin.RawPointer = 0x0b240710 -> 0x00bc5da0 (void *)0x00bc5db4: __NSCFArray)
}
任何线索?提前致谢!
我也有这个问题。我如何将JSON Dictionary值赋给字符串变量?我有一个var'var serverID:String?',并尝试'self.serverID = responseObject [“server_id”]为?字符串'它崩溃Xcode – Sean
我已经成功的这种方法:http://stackoverflow.com/questions/24259756/unable-to-parse-json-from-afnetworkings-responseobject – heycarsten
@heycarsten不幸的是我得到EXC_BAD_INSTRUCTION在模拟器和EXC_BREAKPOINT上带有该代码的设备。 :( – Koesh