我正在为REST端点制作serivce客户端,使用JAX-RS客户端进行HTTP请求,并使用杰克逊对(序列化)JSON实体。为了处理JSR-310(Java8)日期/时间对象,我将com.fasterxml.jackson.datatype:jackson-datatype-jsr310
模块作为依赖项添加到服务客户端,但我没有得到它的工作。JAX-RS客户端对Java8日期/时间的杰克逊(德)序列化
如何配置JAX-RS和/或Jackson使用jsr310模块?
我用下面的依赖关系:
<dependency>
<groupId>javax.ws.rs</groupId>
<artifactId>javax.ws.rs-api</artifactId>
<version>${jax-rs.version}</version>
</dependency>
<dependency>
<groupId>com.fasterxml.jackson.core</groupId>
<artifactId>jackson-annotations</artifactId>
<version>${jackson.version}</version>
</dependency>
<dependency>
<groupId>com.fasterxml.jackson.datatype</groupId>
<artifactId>jackson-datatype-jsr310</artifactId>
<version>${jackson.version}</version>
</dependency>
我不想让服务客户端(被释放库)依赖于任何特定的实现 - 新泽西州一样,所以我只能依靠JAX-RS API。运行我的集成测试我说:
<dependency>
<groupId>org.glassfish.jersey.core</groupId>
<artifactId>jersey-client</artifactId>
<version>${jersey.version}</version>
<scope>test</scope>
</dependency>
<dependency>
<groupId>org.glassfish.jersey.inject</groupId>
<artifactId>jersey-hk2</artifactId>
<version>${jersey.version}</version>
<scope>test</scope>
</dependency>
<dependency>
<groupId>org.glassfish.jersey.media</groupId>
<artifactId>jersey-media-json-jackson</artifactId>
<version>${jersey.version}</version>
<scope>test</scope>
</dependency>
的JAX-RS客户端的实例化是在工厂对象来完成,如下所示:
import javax.ws.rs.Produces;
import javax.ws.rs.client.Client;
import javax.ws.rs.client.ClientBuilder;
@Produces
public Client produceClient() {
return ClientBuilder.newClient();
}
一个典型的DTO是这样的:
import com.fasterxml.jackson.annotation.JsonCreator;
import com.fasterxml.jackson.annotation.JsonProperty;
import com.fasterxml.jackson.annotation.JsonPropertyOrder;
import java.time.Instant;
import static java.util.Objects.requireNonNull;
@JsonPropertyOrder({"n", "t"})
public final class Message {
private final String name;
private final Instant timestamp;
@JsonCreator
public Message(@JsonProperty("n" final String name,
@JsonProperty("t" final Instant timestamp) {
this.name = requireNonNull(name);
this.timestamp = requireNonNull(timestamp);
}
@JsonProperty("n")
public String getName() {
return this.name;
}
@JsonProperty("t")
public Instant getTimestamp() {
return this.timestamp;
}
// equals(Object), hashCode() and toString()
}
的请求做过这样的:
import javax.ws.rs.client.Entity;
import javax.ws.rs.client.WebTarget;
import javax.ws.rs.core.MediaType;
public final class Gateway {
private final WebTarget endpoint;
public Message postSomething(final Something something) {
return this.endpoint
.request(MediaType.APPLICATION_JSON_TYPE)
.post(Entity.json(something), Message.class);
}
// where Message is the class defined above and Something is a similar DTO
}
JSON序列化和反序列化工作正常的字符串,整型,BigIntegers,列表等。然而,当我做这样的事情在我的测试System.out.println(gateway.postSomthing(new Something("x", "y"));
我得到以下异常:
com.fasterxml.jackson.databind.exc.InvalidDefinitionException: Cannot construct instance of `java.time.Instant` (no Creators, like default construct, exist): no String-argument constructor/factory method to deserialize from String value ('Fri, 22 Sep 2017 10:26:52 GMT')
at [Source: (org.glassfish.jersey.message.internal.ReaderInterceptorExecutor$UnCloseableInputStream); line: 1, column: 562] (through reference chain: Message["t"])
at org.example.com.ServiceClientTest.test(ServiceClientTest.java:52)
Caused by: com.fasterxml.jackson.databind.exc.InvalidDefinitionException:
Cannot construct instance of `java.time.Instant` (no Creators, like default construct, exist): no String-argument constructor/factory method to deserialize from String value ('Fri, 22 Sep 2017 10:26:52 GMT')
at [Source: (org.glassfish.jersey.message.internal.ReaderInterceptorExecutor$UnCloseableInputStream); line: 1, column: 562] (through reference chain: Message["t"])
at org.example.com.ServiceClientTest.test(ServiceClientTest.java:52)
从中我得出结论,杰克逊没有按不知道如何将字符串反序列化为Instants。我发现了关于这个主题的博客和SO问题,但是我没有找到关于如何使其工作的明确解释。
请注意,我希望服务客户端处理日期字符串,如"Fri, 22 Sep 2017 10:26:52 GMT"
以及"2017-09-22T10:26:52.123Z"
,但我希望它始终序列化为ISO 8601日期字符串。
谁可以解释如何使反序列化成Instant
工作?
如果JavaTimeModule未在ObjectMapper中注册,通常会发生这种情况:https://github.com/FasterXML/jackson-modules-java8#user-content-registering-modules –
@Hugo我读到了这个,但我不清楚如何做这个注册。你能否将这一切归结为答案? – Rinke
我从来没有同时使用泽西和杰克逊,所以不知道如何去做。我通常以编程方式设置ObjectMapper(如前面评论中提供的链接)。无论如何,也许这可以帮助:https://stackoverflow.com/q/18872931/7605325 –