0
假设我有两个json对象,我需要合并它们。将json对象与数组合并
css: [{
drag: "mode() == 'layout'",
ui_draggable: "mode() == 'layout'"
}]
css: [{
someclass : true
}]
我想结束了:
css: [{
drag: "mode() == 'layout'",
ui_draggable: "mode() == 'layout'",
someclass : true
}]
一些进一步审理中我想出了这个之后,但我认为我有地方一些错误或它的代码无用行。
我稍微玩了一段代码就想出了这段代码。我的需求不需要递减两个以上的级别,所以这很好。我相信它可能会有很大的改进,但它对绑定淘汰赛非常有用。下面是我如何使用它来扩展jQuery的不显眼knockoutjs
var settings = {
text: 'SelectedCard().CardData.Title',
visible: "mode() != 'edit' || !isMyCard()",
css: [{ drag: "mode() == 'layout'" , selectedElement: "selectedCardElement() == '_titlePreview'"}]
};
var settings2 =
{
css: [{ drag: "mode() == 'layout'"}]
};
var settings3 = merge(settings, settings2);
function merge(first, second) {
for (var a1 in first) {
// if second object is null we are finished.
used.push(a1);
if (second[a1] == null) {
continue;
} else {
var ob2 = second[a1];
if (typeof (first[a1]) != typeof (ob2)) {
throw new Error("conflicting properties named:" + a1);
}
if ($.isArray(first[a1])) {
for (var i = 0; i < ob2.length; i++) {
first[a1].push(ob2[i]);
}
} else {
// matching property.
return merge(first[a1], second[a1]);
}
}
}
for (var a2 in second) {
if (used.indexOf(a2) < 0) {
first[a2] = second[a2];
}
}
return first;
}
这些不是“JSON对象”。 JSON是一个字符串。这些是物体。 –
https://www.google.com/search?q=javascript+objects+merge SO不是您的[个人研究助理](http://meta.stackexchange.com/a/128553/165612)。 – iambriansreed
Exact Duplicate:http://stackoverflow.com/questions/171251/how-can-i-merge-properties-of-two-javascript-objects-dynamically – iambriansreed