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我正在计算一个词的每周发生次数。也就是说,本周每个单词是否比前一周更频繁。为此,我有点卡住了。我做了以下内容:PySpark每周发生的计算
m = sc.parallelize(["oded,12-12-2018", "oded,12-03-2018", "oded,12-12-2018", "oded,12-06-2018", "oded2,12-02-2018", "oded2,12-02-2018"])
m = m.map(lambda line: line.split(','))
weekly = m.map(lambda line: (line[0], (parse(line[1]).strftime("%V%y"))))
s = sql.createDataFrame(daily)
s.groupby("_1", "_2").count().sort("_2")
结果是:
+-----+----+-----+
| _1| _2|count|
+-----+----+-----+
|oded2|4818| 2|
| oded|4918| 2|
| oded|5018| 2|
+-----+----+-----+
我该如何去让28:9 0 =(2 - 2)与oded2:2 =(2 - 0)
谢谢!
完美!谢谢! – Himberjack