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鉴于下面的回应,我将如何得到像标题一样的东西?JSON - 如何获得数组中的特定值?
jsonFlickrFeed({
"title": "Thing",
"link": "http://www.flickr.com/photos/tags/",
"description": "",
"items": [
{
"title": "Title",
"link": "http://www.flickr.com/photos/123",
"media": {"m":"http://farm6.staticflickr.com/123.jpg"},
},
{
"title": "Title2",
"link": "http://www.flickr.com/photos/1234",
"media": {"m":"http://farm6.staticflickr.com/1234.jpg"},
},
})
我想要做的事,如:
for (var i=0; i<xml.responseText.length;i++) {
var x = (xml.responseText.items.title[i]);
document.write(x)
}
我在做什么错在这里?
这是不完整的代码。我们推断xml.responseText是这个神秘的jsonFlickrFeed函数的结果吗? –
@hubsonbropa xml.responseText结果在上面jsonFlickrFeed –
@hubsonbropa jsonFlickrFeed是我得到的时候我console.log(xml.responseText)...想知道如何获得具体的事情在jsonFlickrFeed –