2011-04-27 66 views
1
NSString *urlVal = @"http://at.azinova.info/green4care/iphone/viewImage.php?id="; 

    NSString *urlVal1 = [urlVal stringByAppendingString:selectedCountryw]; 



    NSURL *url1 = [NSURL URLWithString:urlVal1]; 

    NSString *resultString = [NSString stringWithContentsOfURL:url1 encoding:NSUTF8StringEncoding error:nil]; 


    NSMutableArray *arycountries2 = [resultString componentsSeparatedByString:@"#***#"]; 
    arraycountries = [[NSMutableArray alloc]initWithArray:arycountries2]; 

我想显示图像url(resultstring)到tableview。我提到three20和lazytable,但它不适合我。下面iPhone多重图像加载

- (NSInteger)numberOfSectionsInTableView:(UITableView *)tableView { 
    return 1; 
} 


// Customize the number of rows in the table view. 
- (NSInteger)tableView:(UITableView *)tableView numberOfRowsInSection:(NSInteger)section { 
    return [arraycountries count]; 
} 


// Customize the appearance of table view cells. 
- (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath { 

    static NSString *CellIdentifier = @"Cell"; 

    UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:CellIdentifier]; 
    if (cell == nil) { 
     cell = [[[UITableViewCell alloc] initWithStyle:UITableViewCellStyleDefault reuseIdentifier:CellIdentifier] autorelease]; 
    } 
    cell.imageView.image = [UIImage imageNamed:[arraycountries objectAtIndex:indexPath.row]]; 


    return cell; 
} 

实现代码如下代码给请帮我

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thankz krishnabhadra..now我知道如何接受答案 – 2011-04-27 10:09:59

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是你想在单元格中显示图像? – 2011-04-27 10:58:58

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请不要再创建新账户再次提出同样的问题。这被认为是滥用系统,可以保证中止。 – Will 2011-04-27 17:42:17

回答