将XML转换为字符串[]帮助

Question

我遇到麻烦将XML文档的内容转换为int []或字符串[] 我将20个不同图片框的x和y坐标保存在屏幕上一个拼图程序）到一个xml文件，现在正在尝试加载已保存的坐标并将拼图碎片更新到已保存的位置。

继承人我的代码：

XmlWriter XmlWriter1; 
    XmlReader XmlReader1; 
    private void Form1_Load(object sender, EventArgs e) 
    { 
     //------------------------------------------------- 
     //Load Events 
     //------------------------------------------------- 
     SavedPositions = new int[40]; 
    } 
    //------------------------------------------------------- 
    //Saves The Current Tile Locations To A Hidden XML File 
    //------------------------------------------------------- 
    public void SavePicPositionsXML() 
    { 
     using (XmlWriter1 = XmlWriter.Create("SavedPuzzle.xml")) 
     { 
      XmlWriter1.WriteStartDocument(); 
      XmlWriter1.WriteStartElement("MTiles"); 
      for (int i = 0; i < JigsawImgCount; i++) 
      { 
       XmlWriter1.WriteStartElement("Tile"); 
       XmlWriter1.WriteElementString("X",Convert.ToString(MTiles[i].Pic.Location.X)); 
       XmlWriter1.WriteElementString("Y",Convert.ToString(MTiles[i].Pic.Location.Y)); 
       XmlWriter1.WriteEndElement(); 
      } 
      XmlWriter1.WriteEndElement(); 
      XmlWriter1.WriteEndDocument(); 
     } 
    } 
    //--------------------------------------------------------------- 
    //Reads Text From A Hidden Xml File & Adds It To A String Array 
    //--------------------------------------------------------------- 
    private int ReadXmlFile(int Z) 
    { 
     XmlReader1 = XmlReader.Create("SavedPuzzle.xml"); 
     XmlReader1.MoveToContent(); 
     while (XmlReader1.Read()) 
     { 

     } 
     // SavedPositions[B] = Convert.ToInt32(XmlReader1.Value.ToString()); 
     return SavedPositions[Z]; 
    } 
    //------------------------------------------------- 
    //Loads Saved Tile Positions From A Hidden Xml File 
    //------------------------------------------------- 
    private void LoadPositionsXML() 
    { 
     G = 0; 
     for (int i = 0; i < JigsawImgCount; i++) 
     { 
      LineX = ReadXmlFile(G); 
      LineY = ReadXmlFile(G + 1); 
      MTiles[i].Pic.Location = new Point(LineX, LineY); 
      G = G + 2; 
     } 
    } 

什么我做错了???

Answer 1

您的ReadXmlFile方法没有做任何事情。

考虑使用XmlDocument或XDocument而不是XmlWriter和XmlReader。他们更容易处理。

Answer 2

试试这个：

  XmlDocument document = new XmlDocument(); 
     document.Load(@"D:/SavedPuzzle.xml"); 
     XmlNode topNode = document.GetElementsByTagName("MTiles")[0]; 
     foreach (XmlNode node in topNode.ChildNodes) 
     { 
      int X = Int32.Parse(node.ChildNodes[0].InnerText); 
      int Y = Int32.Parse(node.ChildNodes[1].InnerText); 
     } 

Answer 3

以下LinqToXML语句将提取所有瓷砖到它们存储在文档中的顺序列表。

我假设，看起来像这样的XML文件：

<xml> 
    <MTiles> 
    <Tile> 
     <X>1</X> 
     <Y>10</Y> 
    </Tile> 
    <Tile> 
     <X>2</X> 
     <Y>20</Y> 
    </Tile> 
    <Tile> 
     <X>3</X> 
     <Y>30</Y> 
    </Tile> 
    <Tile> 
     <X>4</X> 
     <Y>40</Y> 
    </Tile> 
    </MTiles> 
</xml> 

而这个代码将加载它，并提取所有的瓦到枚举列表。记得把using System.Xml.Linq在文件的顶部，并建立针对最近足够的框架（IIRC，据介绍在.net 3.5）

XDocument doc = XDocument.Load(/* path to the file, or use an existing reader */); 
var tiles = from tile in doc.Descendants("Tile") 
      select new 
      { 
       X = (int)tile.Element("X"), 
       Y = (int)tile.Element("Y"), 
      }; 
foreach (var tile in tiles) 
{ 
    Console.WriteLine("Tile: x={0}, y={1}", tile.X, tile.Y); 
} 

从代码的输出上面使用我指定的XML文件是：

Tile: x=1, y=10 
Tile: x=2, y=20 
Tile: x=3, y=30 
Tile: x=4, y=40 

编辑： 如果你只是想所有的X - 值作为一个整数数组，下面的LINQ查询会的工作：

int[] allXValues = (from tile in doc.Descendants("Tile") 
        select (int)tile.Element("X")).ToArray();