1
我试图动态更新一个MySql表,$query
看起来正确时,我回声它,但由于某种原因,当我将代码插入MySql查询时,它不起作用。动态更新MySql表
$b = 1;
$query_a = array();
$vars = array();
$result = mysql_query("SELECT * FROM my_table");
for ($i = 0; $i < mysql_num_fields($result); $i++) {
$vars[] = mysql_field_name($result,$b);
$b++;
}
foreach ($vars as $v)
{
if (isset($_GET[$v]))
{
$isclean = $_GET[$v];
$query[] = $v.' = '.$isclean.'';
}
}
$query = implode(',', $query);
mysql_query("UPDATE my_table SET $query WHERE UIN = '1'");
它给了什么错误? – encodes 2012-04-13 11:02:11
make echo mysql_error();如果有什么问题 – riso 2012-04-13 11:02:11