2017-10-08 158 views
-1

尝试在类内部打印函数来打印声明的变量。C++类错误没有指定类型

class MovieData{ 
private: 
    int year, runtime; 
    string title, director; 
public: 
    MovieData(string t, string d, int y, int rt){ 
     year = y; 
     runtime = rt; 
     title = t; 
     director = d; 
    } 

    print{ 
     cout << title << " (" << year << "). Directed by " << director << ". (" << rt << " minutes)"; 
    } 
}; 

错误就出来这样的:

main.cpp:20:9: error: ‘print’ does not name a type 
    print{ 
    ^
main.cpp: In function ‘void doIt(std::string, std::string, int, int)’: 
main.cpp:33:5: error: ‘class MovieData’ has no member named ‘print’ 
md.print(); 

回答

5

你需要print后的括号以及返回类型,就像这样:void print() {...}

+1

谢谢我正在学习cPP的过程中,这是我第一次用C++编写的类,我应该看到它只是由于某种原因而滑落了我的脑海。谢谢 :) – Coderz