Android视频查看另一个线程＆问题与Android 2.1

Question

我想在android视频视图流视频表单url。我使用示例API代码，做小的修改在实现我的需要。我的代码是

public class VideoViewDemo extends Activity { 

private static final String TAG = "VideoViewDemo"; 
private String current; 

/** 
* TODO: Set the path variable to a streaming video URL or a local media 
* file path. 
*/ 
private String path = "http://www.boisestatefootball.com/sites/default/files/videos/original/01%20-%20coach%20pete%20bio_4.mp4"; 
private VideoView mVideoView; 

@Override 
public void onCreate(Bundle icicle) { 
    super.onCreate(icicle); 
    setContentView(R.layout.videoview); 
    mVideoView = (VideoView) findViewById(R.id.surface_view); 
    runOnUiThread(new Runnable() { 
     public void run() { 
      playVideo(); 
     } 
    }); 
} 

private void playVideo() { 
    try { 
     // final String path = path; 
     Log.v(TAG, "path: " + path); 
     if (path == null || path.length() == 0) { 
      Toast.makeText(VideoViewDemo.this, "File URL/path is empty", 
        Toast.LENGTH_LONG).show(); 

     } else { 
      // If the path has not changed, just start the media player 
      if (path.equals(current) && mVideoView != null) { 
       mVideoView.start(); 
       mVideoView.requestFocus(); 
       return; 
      } 
      current = path; 
      mVideoView.setVideoPath(getDataSource(path)); 
      mVideoView.start(); 
      mVideoView.setMediaController(new MediaController(this)); 
      mVideoView.requestFocus(); 

     } 
    } catch (Exception e) { 
     Log.e(TAG, "error: " + e.getMessage(), e); 
     if (mVideoView != null) { 
      mVideoView.stopPlayback(); 
     } 
    } 
} 

private String getDataSource(String path) throws IOException { 
    if (!URLUtil.isNetworkUrl(path)) { 
     return path; 
    } else { 
     URL url = new URL(path); 
     URLConnection cn = url.openConnection(); 
     cn.connect(); 
     InputStream stream = cn.getInputStream(); 
     if (stream == null) 
      throw new RuntimeException("stream is null"); 
     File temp = File.createTempFile("mediaplayertmp", "dat"); 
     temp.deleteOnExit(); 
     String tempPath = temp.getAbsolutePath(); 
     FileOutputStream out = new FileOutputStream(temp); 
     byte buf[] = new byte[128]; 
     do { 
      int numread = stream.read(buf); 
      if (numread <= 0) 
       break; 
      out.write(buf, 0, numread); 
     } while (true); 
     try { 
      stream.close(); 
     } catch (IOException ex) { 
      Log.e(TAG, "error: " + ex.getMessage(), ex); 
     } 
     return tempPath; 
    } 
} 
} 

在这里你可以看到我使用uithread的视频流通过我的上线。就是有什么办法来处理这

我想什么是

new Thered(new Runnable() { 
     public void run() { 
      playVideo(); 
     } 
    }).start(); 

但它无法

而且还同时在Android 2.2的第一个代码运行运行，它显示error(-38,0)我n Android 2.1这个错误是什么？我检查了This File，但无法找出这是什么错误？

有人可以指导我吗？

Answer 1

您不需要获取整个视频，并将其保存在文件系统中，然后运行它。您提到的视频具有32Mb大小，并且需要很长时间才能通过网络获取。相反，您可以直接链接到videoview，它会逐步获取/缓冲视频并播放它。您试图在UI线程中获取视频数据，这是不可接受的。这里是更正的代码，你可以检查它。

public class VideoViewDemo extends Activity { 

private static final String TAG = "VideoViewDemo"; 
private String current; 

/** 
* TODO: Set the path variable to a streaming video URL or a local media 
* file path. 
*/ 
private String path = "http://www.boisestatefootball.com/sites/default/files/videos/original/01%20-%20coach%20pete%20bio_4.mp4"; 
private VideoView mVideoView; 

private Handler handler; 

@Override 
public void onCreate(Bundle icicle) { 
    super.onCreate(icicle); 
    handler = new Handler(); 
    setContentView(R.layout.videoview); 
    mVideoView = (VideoView) findViewById(R.id.surface_view); 
/* runOnUiThread(new Runnable() { 
     public void run() { 
      playVideo(); 
     } 
    }); 
*/  
    playVideo(); 
    Log.v(TAG, "activity oncreate finished"); 
} 

private void playVideo() { 
    try { 
     // final String path = path; 
     Log.v(TAG, "path: " + path); 
     if (path == null || path.length() == 0) { 
      Toast.makeText(VideoViewDemo.this, "File URL/path is empty", 
        Toast.LENGTH_LONG).show(); 

     } else { 
      // If the path has not changed, just start the media player 
      if (path.equals(current) && mVideoView != null) { 
       mVideoView.start(); 
       mVideoView.requestFocus(); 
       return; 
      } 
      current = path; 

      mVideoView.setVideoPath(path); 
      mVideoView.start(); 
      mVideoView.setMediaController(new MediaController(VideoViewDemo.this)); 
      mVideoView.requestFocus(); 

     } 
    } catch (Exception e) { 
     Log.e(TAG, "error: " + e.getMessage(), e); 
     if (mVideoView != null) { 
      mVideoView.stopPlayback(); 
     } 
    } 
} 

}