2014-03-06 69 views
0

我有这个线程瓦亭对的onTouchEvent()从活动中唤醒等待线程触摸事件?

private Runnable disconnectCallback = new Runnable() { 
    @Override 
    public void run() { 
    // Perform any required operation on disconnect 
     runOnUiThread(new Runnable() { 

      @Override 
      public void run() { 
       // TODO Auto-generated method stub 
       Toast.makeText(getBaseContext(),"Your session expired Please Login again",Toast.LENGTH_SHORT).show(); 
       try { 
        wait(); 
       } catch (InterruptedException e) { 
        e.printStackTrace(); 
       } 

       final Logout l=new Logout(); 
       l.setContext(Ac2.this);// passing context of Ac3.java to Logout.java 
       l.execute(sessid,uname); 
      } 
     }); 
    } 
}; 

我想是当用户触摸手机屏幕通知此等待的线程..

回答

0
private Runnable disconnectCallback = new Runnable() { 
    @Override 
    public void run() { 
     // Perform any required operation on disconnect 
     runOnUiThread(new Runnable() { 

      @Override 
      public void run() { 
       // TODO Auto-generated method stub 
       Toast.makeText(getBaseContext(), 
         "Your session expired Please Login again", 
         Toast.LENGTH_SHORT).show(); 
       try { 
        synchronized (disconnectCallback) { 
         disconnectCallback.wait(); 
        } 
       } catch (InterruptedException e) { 
        e.printStackTrace(); 
       } 

       final Logout l = new Logout(); 
       l.setContext(Ac2.this);// passing context of Ac3.java to 
             // Logout.java 
       l.execute(sessid, uname); 
      } 
     }); 
    } 
}; 

和onTouch事件调用:

disconnectCallback.notifyAll(); 
+0

它提供了以下错误:java.lang.IllegalMonitorStateException:由线程等待对象之前没有锁定() – user3371398

+0

呼叫等待功能也disconnectCallback,如:disconnectCallback.wait(); –

+0

顺便说一句我建议在UI线程上运行以外的等待相关代码。 –

0

试试这个

private Runnable disconnectCallback = new Runnable() { 
    @Override 
    public void run() { 
     // Perform any required operation on disconnect 
     runOnUiThread(new Runnable() { 

      @Override 
      public void run() { 
       // TODO Auto-generated method stub 
       Toast.makeText(getBaseContext(), 
         "Your session expired Please Login again", 
         Toast.LENGTH_SHORT).show(); 

      } 
     }); 
     try { 
      synchronized(disconnectCallback){ 
      disconnectCallback.wait(); 
      final Logout l=new Logout(); 
      l.setContext(Ac2.this);// passing context of Ac3.java to Logout.java 
      l.execute(sessid,uname); 

      } 
     } catch (InterruptedException e) { 
      e.printStackTrace(); 
     } 


    } 
}; 

内onTouch

synchronized (disconnectCallback) { 
     disconnectCallback.notify(); 
    } 
+0

您是否正在注销内进行与UI相关的任务? – Sonali8890

+0

发生以下错误:完成的活动(在应用程序MyapplicationName中)未响应 – user3371398

+0

In Logout.java它调用一个php文件并移至登录屏幕(上一活动) – user3371398