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我执行使用SQLSRV存储过程中的PHP代码是这样的:执行存储过程SQLSRV在PHP
$tsql_callSP = "{call cnt.stproc1(?)}";
$rotCode = '1111';
$params = array(
array($rotCode, SQLSRV_PARAM_IN),
);
$serverName = "xxxxxxx\wwwwwww"; //serverName\instanceName
$connectionInfo = array("Database"=>"aaaaaaaaaaa", "UID"=>"bbbbbbb", "PWD"=>"ccccccc");
$conn = sqlsrv_connect($serverName, $connectionInfo);
/* Execute the query. */
$stmt3 = sqlsrv_query($conn, $tsql_callSP, $params);
if($stmt3 === false)
{
echo "Error in executing statement 3.\n";
die(print_r(sqlsrv_errors(), true));
}
存储过程是成功的DB执行和做的事情必须做,但在我的PHP代码,我总是落在failiure如果(stmt3 ===假)收到以下错误:
Array ([0] => Array ([0] => 01000 [SQLSTATE] => 01000 [1] => 0 [code] => 0 [2] => [Microsoft][ODBC Driver 11 for SQL Server][SQL Server]0510620150922777 [message] => [Microsoft][ODBC Driver 11 for SQL Server][SQL Server]0510620150922777) [1] => Array ([0] => 01000 [SQLSTATE] => 01000 [1] => 0 [code] => 0 [2] => [Microsoft][ODBC Driver 11 for SQL Server][SQL Server]UPDATE 004 [message] => [Microsoft][ODBC Driver 11 for SQL Server][SQL Server]UPDATE 004))
这里有什么问题?为什么它执行得很好,但驱动程序处理我这个错误?
sproc返回什么?也许那个回报价值就是欺骗某个层面,认为这是失败。 –