Laravel查询生成器加入

Question

下午好点子，我想请求你的帮助。

请帮我将这个查询应用到Laravel查询生成器中。我只知道如何使用原始查询查询数据库。

查询：

SELECT users.first_name, users.last_name, users.id as userID, bookmarks.id, 
products.title, products.price, products.id AS productID FROM users, 
products, bookmarks WHERE bookmarks.user_id = $user_id AND products.id = 
bookmarks.product_id AND users.id = products.user_id; 

谢谢你那些人会帮助我。

Answer 1

$result = DB::select(DB::raw('custom_query')); 
    $user_name = $result[0]->first_name.' '.$result[0]->last_name; 

Answer 2

Use this Laravel Query. 

$response = DB::table('users as u')->select(
       'u.id as userId', 
       'u.first_name', 
       'u.last_name', 
       'b.id as bookmarkId', 
       'p.id as productId',`enter code here` 
       'p.title', 
       'p.price' 
      ) 
       ->leftjoin('bookmarks as b', 'b.user_id', '=', 'u.id') 
       ->leftjoin('products as p', 'p.user_id', '=', 'u.id') 
       ->where('u.id', $userId)->get(); 

Answer 3

SELECT users.first_name，users.last_name，users.id如用户ID， bookmarks.id，products.title，products.price，products.id AS FROM的productID用户，产品，书签WHERE bookmarks.user_id = $ user_id AND products.id = bookmarks.product_id AND users.id = products.user_id;

你可以使用方法的雄辩，只是访问关系，但如果你想laravel查询方法。您可以使用DB :: raw来拥有自己的原始查询。

DB::select(DB::raw("Select a.first_name, a.last_name, a.id as user_id, b.id, c.title, c.price, c.id from users as a INNER JOIN bookmarks as b on b.user_id = $user_id INNER JOIN Products as c on c.id = b.product_id where user_id = c.user_id")); 

这只是一个例子，它仍然取决于您如何操纵查询。

爱， 船尾