使用POST从iPhone应用程序发送数据到web表单

Question

我想从我的iPhone应用程序使用GET发送数据（用户名和密码）到在线表单。

这是我的源代码，但问题是没有数据存储在我的数据库中。

NSString *post =[[NSString alloc] initWithFormat:@"email=%@&password=%@",enterUserName.text,enterPass.text]; 
NSURL *url=[NSURL URLWithString:@"http://planetimpressions.com/contacts/imagecomm_register.php"]; 

NSLog(post); 
NSData *postData = [post dataUsingEncoding:NSASCIIStringEncoding allowLossyConversion:YES]; 

NSString *postLength = [NSString stringWithFormat:@"%d", [postData length]]; 

NSMutableURLRequest *request = [[[NSMutableURLRequest alloc] init] autorelease]; 
[request setURL:url]; 
[request setHTTPMethod:@"POST"]; 
[request setValue:postLength forHTTPHeaderField:@"Content-Length"]; 
[request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Content-Type"]; 
[request setHTTPBody:postData]; 

/* when we user https, we need to allow any HTTPS cerificates, so add the one line code,to tell teh NSURLRequest to accept any https certificate, i'm not sure about the security aspects 
*/ 

[NSURLRequest setAllowsAnyHTTPSCertificate:YES forHost:[url host]]; 

NSError *error; 
NSURLResponse *response; 
NSData *urlData=[NSURLConnection sendSynchronousRequest:request returningResponse:&response error:&error]; 

NSString *data=[[NSString alloc]initWithData:urlData encoding:NSUTF8StringEncoding]; 
NSLog(@"%@",data); 

Web表单的源代码如下。

if(isset($_GET['submit'])){ 
$email = $_GET['email']; 
$password = $_GET['password']; 
$conn = mysql_connect("mysql", "*****", "*****"); 
if(!$conn) 
{ 
    die('Could not connect: ' . mysql_error()); 
} 
mysql_select_db("imagecomm_users"); 
$sql = "INSERT INTO registration(number, email, password) VALUES (null, 
'$email', '$password')"; 
if (!mysql_query($sql,$conn)) 
    { 
    die('Error: ' . mysql_error()); 
    } 
} 
?> 

我测试了脚本，它们工作得很好。我可以使用在线表单将用户名和密码存储到数据库中。我遇到的唯一问题是连接到应用程序的在线表单。

我没有收到控制台中的任何错误消息或任何意外。只是，没有任何反应。我会感谢任何帮助。谢谢

Answer 1

我用UIWebView解决了这个问题。

代码来调用UIWebView的是 -

在头文件中声明

UIWebView *myWebView 
@property(nonatomic, retain) IBOutlet UIWebView ... 

在实现文件 -

[myWebView loadRequest:[NSURLRequest requestWithURL:[NSURL URLWithString:URLTOCALL]]]; 

和两种方法 -

- (void)webViewDidFinishLoad:(UIWebView *)webView 

和

- (void)webViewDidStartLoad:(UIWebView *)webView{ 

Answer 2

使用ASIHTTP请求与服务器的请求/响应。从这里下载ASIHTTP文件：http://github.com/pokeb/asi-http-request/tarball/master。 在项目中集成并添加到标题以及在.h文件中定义委托。 现在你可以在你的文件中使用这段代码。

- (void)requestAuth { 
    NSString* urlString = [NSString stringWithFormat:@" http://planetimpressions.com/contacts/imagecomm_register.php 
    "]; 
    NSURL *url = [NSURL URLWithString:self.urlString]; 
    ASIFormDataRequest *request = [[ASIFormDataRequest alloc] initWithURL:url]; 

    if (!request) { 
     NSLog(@"Request prepared"); 
     return nil; 
    } 

    [request setPostValue: enterUserName.text forKey:@”email”]; 

    [request setPostValue: enterPass.text forKey:@"password"]; 
    [request setTimeOutSeconds:30]; 

    #if __IPHONE_OS_VERSION_MAX_ALLOWED >= __IPHONE_4_0 
    [request setShouldContinueWhenAppEntersBackground:YES]; 
    #endif 

    [request setDelegate:self]; 
    [request setDidFailSelector:@selector(ASIHTTPUploadFailed:)]; 
    [request setDidFinishSelector:@selector(ASIHTTPUploadFinished:)]; 
    [request startAsynchronous]; 
} 

- (void)ASIHTTPUploadFinished:(ASIHTTPRequest *)theRequest { 
    //Parse coming response 
    NSLog(@"%@",[theRequest responseString]); 
} 

- (void)ASIHTTPUploadFailed:(ASIHTTPRequest *)theRequest { 
    //Parse response if request become failure 
    NSLog(@"%@",[theRequest responseString]); 
}