我正在开发的国家状态级联下拉列表...我回到JSON结果基于countryId
,但我不知道如何填充/在一个新的下拉列表框填满它......如何在jQuery中使用json数据填充下拉列表?
这里就是我使用,
function getstate(countryId) {
$.ajax({
type: "POST",
url: "Reg_Form.aspx/Getstates",
data: "{'countryId':" + (countryId) + "}",
contentType: "application/json; charset=utf-8",
global: false,
async: false,
dataType: "json",
success: function(jsonObj) {
alert(jsonObj.d);
}
});
return false;
}
和警觉给这个,
{"Table" : [{"stateid" : "2","statename" : "Tamilnadu"},
{"stateid" : "3","statename" : "Karnataka"},
{"stateid" : "4","statename" : "Andaman and Nicobar"},
{"stateid" : "5","statename" : "Andhra Pradesh"},
{"stateid" : "6","statename" : "Arunachal Pradesh"}]}
我的aspx页面有这个,
<td>
<asp:DropDownList ID="DLCountry" runat="server" CssClass="dropDownListSkin"
onchange="return getstate(this.value);">
</asp:DropDownList>
</td>
<td>
<asp:DropDownList ID="DLState" runat="server" CssClass="dropDownListSkin">
</asp:DropDownList>
</td>
如何填写DLState
下拉任何建议...
编辑:
当我通过萤火检查我得到了我的AJAX后的反应,
{"d":"{\"Table\" : [{\"stateid\" : \"2\",\"statename\" : \"Tamilnadu\"},{\"stateid\" : \"3\",\"statename\" : \"Karnataka\"},{\"stateid\" : \"4\",\"statename\" : \"Andaman and Nicobar\"},{\"stateid\" : \"5\",\"statename\" : \"Andhra Pradesh\"},{\"stateid\" : \"6\",\"statename\" : \"Arunachal Pradesh\"},{\"stateid\" : \"7\",\"statename\" : \"Assam\"},{\"stateid\" : \"8\",\"statename\" : \"Bihar\"},{\"stateid\" : \"9\",\"statename\" : \"Dadra and N. Haveli\"},{\"stateid\" : \"10\",\"statename\" : \"Daman and Diu\"},{\"stateid\" : \"11\",\"statename\" : \"Delhi\"},{\"stateid\" : \"12\",\"statename\" : \"Goa\"},{\"stateid\" : \"13\",\"statename\" : \"Gujarat\"},{\"stateid\" : \"14\",\"statename\" : \"Haryana\"},{\"stateid\" : \"15\",\"statename\" : \"Himachal Pradesh\"},{\"stateid\" : \"16\",\"statename\" : \"Jammu and Kashmir\"},{\"stateid\" : \"17\",\"statename\" : \"Kerala\"},{\"stateid\" : \"18\",\"statename\" : \"Laccadive Islands\"},{\"stateid\" : \"19\",\"statename\" : \"Madhya Pradesh\"},{\"stateid\" : \"20\",\"statename\" : \"Maharashtra\"},{\"stateid\" : \"21\",\"statename\" : \"Manipur\"},{\"stateid\" : \"22\",\"statename\" : \"Meghalaya\"},{\"stateid\" : \"23\",\"statename\" : \"Mizoram\"},{\"stateid\" : \"24\",\"statename\" : \"Nagaland\"},{\"stateid\" : \"25\",\"statename\" : \"Orissa\"},{\"stateid\" : \"26\",\"statename\" : \"Pondicherry\"},{\"stateid\" : \"27\",\"statename\" : \"Punjab\"},{\"stateid\" : \"28\",\"statename\" : \"Rajasthan\"},{\"stateid\" : \"29\",\"statename\" : \"Sikkim\"},{\"stateid\" : \"30\",\"statename\" : \"Tripura\"},{\"stateid\" : \"31\",\"statename\" : \"Uttar Pradesh\"},{\"stateid\" : \"32\",\"statename\" : \"West Bengal\"}]}"}
看到这一个例子我的回答: http://stackoverflow.com/questions/2403441/jquery-ajax- pass-success-data-into-separate-function/2403573#2403573 – 2010-04-14 13:58:32
在Firefox和Chrome浏览器中使用onchange事件作为下拉列表(或html选择)对我来说并不适用。我使用jQuerys change()代替(http://api.jquery.com/change/)。 – 2010-04-14 14:20:24
@Daniel'$(“#<%= DLState.ClientID%>”)。html(listItems);'这一行似乎有错误...任何suiggestion .. – 2010-04-14 14:26:30