我正在尝试编写一个程序,该程序从文本文件中读取信息并使用结构和联合和cstrings将其复制到数组中。我的文件看起来像这样。Switchcase声明问题。从txt文件读取信息C++
F South Korea
Male Psy Park Jae Sang
31 - 12 - 1977
3 CSCI114 55 CSCI103 44 GangNam 100
S Female Super Junior
5 - 8 - 1978
2 CSCI114 60 CSCI103 80
F People Republic Of China
Unknown James Bond
11 - 12 - 1976
4 CSCI114 54 CSCI124 66 CSCI007 99 CSCI123 28
我的查询是,我写了一个简单的开关案例与一个for循环读取信息基于其标准。例如,每段前面的第一个字母表示学生是外国人,F还是新加坡人,S.根据他们的国籍,我选择将其信息复制到哪个结构/联盟。为了给你一个更好的主意,这是我从原始文本文件中获取信息并处理它后,最终的文本输出文件的样子。
http://i.stack.imgur.com/Bv2YS.jpg
下面是我的,我遇到的麻烦的代码段。似乎char变量是否读取“S”或“F”,我的switch语句只读取它为“F”。
//file to array.
char dateJunk;
int numOfCourses;
int k = 0;
while (!afile.eof())
{
for (int k = 0; k < 3; k++)
{
afile >> locale;
switch (locale)
{
case 'F':
afile.getline(x[k].st.foreignStudent.nationality, MAX);
afile >> x[k].st.foreignStudent.gender;
afile.getline(x[k].st.foreignStudent.name, MAX);
afile >> x[k].st.foreignStudent.bd.day;
afile >> dateJunk;
afile >> x[k].st.foreignStudent.bd.month;
afile >> dateJunk;
afile >> x[k].st.foreignStudent.bd.year;
afile >> x[k].st.foreignStudent.numOfCourses;
for (int i = 0; i < x[k].st.foreignStudent.numOfCourses; i++)
{
afile >> x[i].st.foreignStudent.subjects[k];
afile >> x[i].st.foreignStudent.grades[k];
}
break;
case 'S':
afile >> x[k].st.localStudent.gender;
afile.getline(x[k].st.localStudent.name, MAX);
afile >> x[k].st.localStudent.bd.day;
afile >> dateJunk;
afile >> x[k].st.localStudent.bd.month;
afile >> dateJunk;
afile >> x[k].st.localStudent.bd.year;
afile >> x[k].st.localStudent.numOfCourses;;
for (int i = 0; i < x[k].st.localStudent.numOfCourses; i++)
{
afile >> x[i].st.localStudent.subjects[k];
afile >> x[i].st.localStudent.grades[k];
}
}
}
}
//Tests my cstring arrays to see everything is copied in correctly.
for (int k = 0; k < 3; k++)
{
cout << locale << " " << x[k].st.foreignStudent.nationality;
cout << endl;
cout << x[k].st.foreignStudent.gender;
cout << x[k].st.foreignStudent.name;
cout << endl;
cout << x[k].st.foreignStudent.bd.day << " - ";
cout << x[k].st.foreignStudent.bd.month << " - ";
cout << x[k].st.foreignStudent.bd.year;
cout << endl;
cout << x[k].st.foreignStudent.numOfCourses;
cout << endl;
for(int i = 0; i < x[k].st.foreignStudent.numOfCourses; i++)
{
cout << x[i].st.foreignStudent.subjects[k] << " ";
cout << x[i].st.foreignStudent.grades[k] << " ";
}
cout << endl;
}
return 0;
}
以下是代码整体。
#include <iostream>
#include <fstream>
#include <cstdlib>
#include <ctime>
using namespace std;
const int MAX = 80;
struct Birthday
{
char day[MAX];
char month[MAX];
char year[MAX];
};
struct Local
{
char name[MAX];
char nationality[MAX];
char gender[MAX];
Birthday bd;
char subjects [MAX][MAX];
char grades [MAX][MAX];
int numOfCourses;
};
struct Foreigner
{
char name[MAX];
char nationality[MAX];
char gender[MAX];
Birthday bd;
char subjects [MAX][MAX];
char grades [MAX][MAX];
int numOfCourses;
};
union Student
{
Local localStudent;
Foreigner foreignStudent;
};
enum CountryType {S, F};
struct UowStudents
{
CountryType ct;
Student st;
};
int fileToArray (fstream& afile, char fileName [], UowStudents* x, char& locale);
int main()
{
srand(time_t(NULL));
fstream afile;
UowStudents x [MAX];
char fileName[MAX];
char locale;
cout << "Enter filename: ";
cin >> fileName;
int size = fileToArray (afile, fileName, x, locale);
}
int fileToArray (fstream& afile, char fileName [], UowStudents* x, char& locale)
{
afile.open(fileName, ios::in);
if (!afile)
{
cout << fileName << "could not be opened for read" << endl;
exit (-1);
}
//file to array.
char dateJunk;
int numOfCourses;
int k = 0;
while (!afile.eof())
{
for (int k = 0; k < 3; k++)
{
afile >> locale;
switch (locale)
{
case 'F':
afile.getline(x[k].st.foreignStudent.nationality, MAX);
afile >> x[k].st.foreignStudent.gender;
afile.getline(x[k].st.foreignStudent.name, MAX);
afile >> x[k].st.foreignStudent.bd.day;
afile >> dateJunk;
afile >> x[k].st.foreignStudent.bd.month;
afile >> dateJunk;
afile >> x[k].st.foreignStudent.bd.year;
afile >> x[k].st.foreignStudent.numOfCourses;
for (int i = 0; i < x[k].st.foreignStudent.numOfCourses; i++)
{
afile >> x[i].st.foreignStudent.subjects[k];
afile >> x[i].st.foreignStudent.grades[k];
}
break;
case 'S':
afile >> x[k].st.localStudent.gender;
afile.getline(x[k].st.localStudent.name, MAX);
afile >> x[k].st.localStudent.bd.day;
afile >> dateJunk;
afile >> x[k].st.localStudent.bd.month;
afile >> dateJunk;
afile >> x[k].st.localStudent.bd.year;
afile >> x[k].st.localStudent.numOfCourses;;
for (int i = 0; i < x[k].st.localStudent.numOfCourses; i++)
{
afile >> x[i].st.localStudent.subjects[k];
afile >> x[i].st.localStudent.grades[k];
}
}
}
}
//Tests my cstring arrays to see everything is copied in correctly.
//The print for foreign student cstrings also has information for the
//one Singaporean student "S" in the middle. Singaporean must go into
//the local cstrings.
for (int k = 0; k < 3; k++)
{
cout << locale << " " << x[k].st.foreignStudent.nationality;
cout << endl;
cout << x[k].st.foreignStudent.gender;
cout << x[k].st.foreignStudent.name;
cout << endl;
cout << x[k].st.foreignStudent.bd.day << " - ";
cout << x[k].st.foreignStudent.bd.month << " - ";
cout << x[k].st.foreignStudent.bd.year;
cout << endl;
cout << x[k].st.foreignStudent.numOfCourses;
cout << endl;
for(int i = 0; i < x[k].st.foreignStudent.numOfCourses; i++)
{
cout << x[i].st.foreignStudent.subjects[k] << " ";
cout << x[i].st.foreignStudent.grades[k] << " ";
}
cout << endl;
}
//as you can see, everything gets copied into localStudent struct as well.
for (int k = 0; k < 3; k++)
{
cout << x[k].st.localStudent.gender;
cout << x[k].st.localStudent.name;
cout << endl;
cout << x[k].st.localStudent.bd.day << " - ";
cout << x[k].st.localStudent.bd.month << " - ";
cout << x[k].st.localStudent.bd.year;
cout << endl;
cout << x[k].st.localStudent.numOfCourses;
cout << endl;
for(int i = 0; i < x[k].st.localStudent.numOfCourses; i++)
{
cout << x[i].st.localStudent.subjects[k] << " ";
cout << x[i].st.localStudent.grades[k] << " ";
}
cout << endl;
}
return 0;
}
[不要使用'while(!eof())'](http://stackoverflow.com/questions/5605125/why-is-iostreameof-inside-a-loop-condition-considered-wrong)。 – chris
并且不要复制/粘贴所有代码,而是提供可用于重现问题的最小块:没有人会在此处读取超过10-15行的代码。无论如何,在调试器下运行一切,看看有什么不对。并添加一些错误处理!我看到100行代码没有一个错误处理的事情。 – stijn
@stijn我以为我在第一个代码框中提供了这个问题块?第二个代码框是整个程序。 –